如何使用sentiwordnet获得同义词集并计算其情感分数

Question

import nltk
from nltk.corpus import sentiwordnet as swn,SentiSynset
swn.senti_synsets('slow')

for this code in python 3.4.3 i am getting output as:

<filter object at 0x0806DE70>

But it should be like:

[SentiSynset('decelerate.v.01'), SentiSynset('slow.v.02'), \
SentiSynset('slow.v.03'), SentiSynset('slow.a.01'),SentiSynset('slow.a.02'), \
SentiSynset('slow.a.04'), SentiSynset('slowly.r.01'),SentiSynset('behind.r.03')]

I am really sorry if my question is vague or silly but i am new to python and nltk and not getting this one.And how can i get the sentiment scores of these synsets using sentiwordnet.

Answer 1

You are using python3 . In python3 filter function returns a filter object instead of list.

senti_synsets method is defined in nltk like this.

def senti_synsets(self, string, pos=None):
        from nltk.corpus import wordnet as wn
        sentis = []
        synset_list = wn.synsets(string, pos)
        for synset in synset_list:
            sentis.append(self.senti_synset(synset.name()))
        sentis = filter(lambda x : x, sentis)
        return sentis

and since you are using python3, senti_synsets method returns a python filter object.

You can convert that filter object into list.

 synsets=list(swn.senti_synsets('slow'))
 synsets

output

[SentiSynset('decelerate.v.01'),
 SentiSynset('slow.v.02'),
 SentiSynset('slow.v.03'),
 SentiSynset('slow.a.01'),
 SentiSynset('slow.a.02'),
 SentiSynset('dense.s.04'),
 SentiSynset('slow.a.04'),
 SentiSynset('boring.s.01'),
 SentiSynset('dull.s.08'),
 SentiSynset('slowly.r.01'),
 SentiSynset('behind.r.03')]

Answer 2

from nltk.corpus import sentiwordnet as swn
good = swn.senti_synsets('good', 'n')

posscore=0
negscore=0
for synst in good:

    posscore=posscore+synst.pos_score()
    negscore=negscore+synst.neg_score()


print(posscore)
print(negscore)

better to get an average.