[英]Changing values between two data.frames in R
I have the following data.frames(sample): 我有以下data.frames(示例):
>df1
number ACTION
1 1 this
2 2 that
3 3 theOther
4 4 another
>df2
id VALUE
1 1 3
2 2 4
3 3 2
4 4 1
4 5 4
4 6 2
4 7 3
. . .
. . .
I would like df2 to become like the following: 我想df2变得如下:
>df2
id VALUE
1 1 theOther
2 2 another
3 3 that
4 4 this
4 5 another
4 6 that
4 7 theOther
. . .
. . .
It can be done 'mannualy' by using the following for each value: 可以通过对每个值使用以下内容来“mannualy”:
df2[df2==1] <- 'this'
df2[df2==2] <- 'that'
.
.
and so on, but is there a way to do it not mannualy? 等等,但有没有办法做到这一点而不是mannualy?
Try 尝试
df2$VALUE <- setNames(df1$ACTION, df1$number)[as.character(df2$VALUE)]
df2
# id VALUE
#1 1 theOther
#2 2 another
#3 3 that
#4 4 this
#5 5 another
#6 6 that
#7 7 theOther
Or use match
或者使用match
df2$VALUE <- df1$ACTION[match(df2$VALUE, df1$number)]
df1 <- structure(list(number = 1:4, ACTION = c("this", "that",
"theOther",
"another")), .Names = c("number", "ACTION"), class = "data.frame",
row.names = c("1", "2", "3", "4"))
df2 <- structure(list(id = 1:7, VALUE = c(3L, 4L, 2L, 1L, 4L, 2L, 3L
)), .Names = c("id", "VALUE"), class = "data.frame", row.names = c("1",
"2", "3", "4", "5", "6", "7"))
You could do: 你可以这样做:
library(qdapTools)
df2$VALUE <- lookup(terms = df2$VALUE, key.match = df1)
Note that for this to work, you will need the proper columns order in df1
. 请注意,要使其正常工作,您需要在df1
使用正确的列顺序。 From ?lookup
从?lookup
key.match key.match
Takes one of the following: (1) a two column data.frame of a match key and reassignment column, (2) a named list of vectors (Note: if data.frame or named list supplied no key reassign needed) or (3) a single vector match key. 采用以下方法之一:(1)匹配键和重新分配列的两列data.frame,(2)一个命名的向量列表(注意:如果data.frame或命名列表未提供密钥重新分配)或(3) )单个矢量匹配键。
Which gives: 这使:
# id VALUE
#1 1 theOther
#2 2 another
#3 3 that
#4 4 this
#5 5 another
#6 6 that
#7 7 theOther
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