字符数组和指针的基本困惑

Question

I am a beginner in pointers. after completing integer arrays and pointers i shifted to character arrays and pointers. i expected the same results but its weird.

int main() {    
    char chararray[20]="Char Array";      
    void printarray(char *);    
    void printarraydirect(char * );

    printf("Passing chararray to funtion printarray\n");    
    printarray(chararray);        
    printf("Printing directly as c in printarraydirect function");        
    printarraydirect(chararray);

     return 0;
}

void printarray(char *c){        
    int i=0;    
    //while(c[i]!= ' ')-----------------------> checks for empty space        
    while(c[i]!='\0')    
    {    
        printf("%c",c[i]);       
        i++;    
    }    
    printf("\n");    
}



void printarraydirect(char * c){        
    printf("Printing c-------------->");        
    printf("%s\n",c);        
    int i=0;        
    printf("Printing c[i]-------------->\n");
    // shows error here , if so why didnt it show me error in printarray function. and why didnt it print the whole array when printed c in printarray function..

    printf("%s\n" c[i]);

}

Answer 1

First of all, you're missing a comma on the line printf("%s\\n" c[i]); . Secondly, c[i] is a single char (the element type of your array), hence the %s formatting is incorrect - it should be %c to print a single character. Or if you wish to print the entire string from that point onwards, you need to pass the address of that element ( &c[i] ), but in this case that is the same as c since i is zero.

Answer 2

Basically %s format specifier expects an address to print to the output stream and it prints until it finds the NULL character( \\0 ). Here when you give simply c the base address of the array is passed as the argument. But when you give c[i] it is the value located at the location (base address + index) ie, addressOf(c) + valueOf(i).