[英]Unix Shell Scripting
I have seen the concept of process substitution.我已经看到了进程替换的概念。 But the following code still give me the syntax error但是下面的代码仍然给我语法错误
script.sh: syntax error at line 44: `<' unexpected
script.sh: syntax error at line 44: `<' unexpected
Here is the code:这是代码:
#!/bin/bash
count=1
FILENAME=$1
JUDGE="YATES"
echo "VALUE OF JUDGE IS $JUDGE"
STATUS=""
#The file is read using while loop , file being supplied as cmd line arg , file simply contains the list of courts .
#cat $FILENAME | while read LINE
while read LINE
do
#Selecting the filepath here $LINE contains the court every time it iterates
FILEPATH=/elFZ/dZcollection/$LINE/DETER_JUDGE
#Checking whether the DETER_JUDGE exists or not ,
cat $FILEPATH >> yatisawhney.txt 2>> yati_errors.txt
#if the DETER_JUDGE file exists then
if [ $? = 0 ]
then
echo "INSIDE IF"
STATUS="Yes"
#cat $FILEPATH | while read -r JUDGELINE
#open the DETER JUDGE file and read the values and updating the JUDGE variable.
while read JUDGELINE
do
line_length=$JUDGELINE
JUDGE=$JUDGE$line_length"||||||"
#JUDGE=1000
done < < ( $FILEPATH )
echo "Value of judge is $JUDGE"
else
FILEPATH="N.A."
STATUS="No"
JUDGE="N.A."
fi
#here I am not getting the updated value
echo $JUDGE >> JUDGE_NAME
echo $count","$LINE","$STATUS","$JUDGE","$FILEPATH >> judgeData.csv
count=`expr "$count" + 1`
JUDGE=""
done < < ( $FILENAME )
I am unable to the fetch the values from the inner while loop.我无法从内部 while 循环中获取值。 However I am able to fetch them inside the loop, once I get outside the values get lost.但是我能够在循环内获取它们,一旦我离开值就会丢失。
The process substitution uses the <(...)
construct, there should be no space between the <
and the left parenthesis.进程替换使用<(...)
构造, <
和左括号之间不应有空格。
To read from a file, you don't need process substitution at all:要从文件中读取,您根本不需要进程替换:
done < "$FILENAME"
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.