如何处理一条不同于所有其他快递路线

Question

I'm currently using the Express router within a NodeJS application. I have simply been using app.use(app.router); for routing and it works well. However, I'm now testing out some new routes and want to handle them differently.

Ideally I would like to be able to say:

var vers2Router = require('./routes/version2');

app.use('/version2', vers2Router);
app.use(app.router);

Can I do this in order to handle all /version2 routes with vers2Router and the rest simply using app.router ?

Answer 1

As of Express version 4.x, app.router has been removed. Routes are now executed in the order they are added.

Now you may use the express.Router because it will allow you to have isolated instances of routes and in your example you could create many routers with their own versioned routes.

Something like this:

// app.js
'use strict';

var express = require('express');
var app = express();

var userRouterV1 = require('./routes/v1/userRouter.js');
var userRouterV2 = require('./routes/v2/userRouter.js');

app.use('/v1/api/users', userRouterV1);
app.use('/v2/api/users', userRouterV2);

app.listen(4000, function () {
  console.log('server up an running');
});

and your isolated routes version 1 :

// /routes/v1/userRouter.js
'use strict';

var express = require('express');
var router = express.Router();

router.get('/', function (req, res) {
  res.send('Hello v1');
});

module.exports = router;

finally your isolated routes version 2 :

// /routes/v2/userRouter.js
'use strict';

var express = require('express');
var router = express.Router();

router.get('/', function (req, res) {
  res.send('Hey v2');
});

module.exports = router;