[英]How to check whether node $N is present in the sequence-of-nodes $S in XQuery?
I know each variable in XQuery which takes an XPath expression can consist of a set of nodes我知道 XQuery 中采用 XPath 表达式的每个变量都可以由一组节点组成
let $x := //cities[@population > '50000']//*
Or或者
let $y := //something/following::*
I would like to know is there a boolean function to check if $z
belongs to these sets of nodes, for example $x
or $y
?我想知道是否有一个布尔函数来检查
$z
属于这些节点集,例如$x
或$y
?
If no, then how can I declare such function to take two variables and return true if the first variable (sequence of nodes ) include the second (a node or sequence of nodes)如果不是,那么如果第一个变量(节点序列)包含第二个(节点或节点序列),我如何声明这样的函数来接受两个变量并返回 true
for a particular purpose I did the following test:出于特定目的,我进行了以下测试:
declare function local:inside($y,$x) as xs:boolean
{
let $r := ? (: want to know if $y include $x or not :)
return $r
};
let $db := doc('products.xq')
let $items := $db/item//*
let $pricesInItems := $db//price[$items//.] (: $db//price[local:inside($items, .)] :)
(: ^ it doesn't work, by the way :)
return $pricesInItems
for this database:对于这个数据库:
<page>
<products>
<item foo="f1">
<price>100 </price>
</item>
<item foo="f2">
<price>200 </price>
</item>
</products>
<price>300 </price>
</page>
A predicate expression or a function which selects all prices where are inside $db/item//*
.一个谓词表达式或一个函数,它选择
$db/item//*
内的所有价格。 Please note this is just an example, I would like to have a general membership function or predicate expression which works for any two variables.请注意这只是一个例子,我想要一个适用于任何两个变量的通用成员函数或谓词表达式。
If you use the =
operator, it will use set-based logic.如果您使用
=
运算符,它将使用基于集合的逻辑。 For example:例如:
let $set := (2, 4, 6, 8, 10)
return ((6 = $set), (7 = $set))
=> (true(), false())
The same applies for comparisons across two sets:这同样适用于两组之间的比较:
(1, 2, 3, 4) = (4, 5, 6)
=> true()
Two approaches to test whether node $N is present in the sequence-of-nodes $S:测试节点 $N 是否存在于节点序列 $S 中的两种方法:
(a) exists($S intersect $N)
(a)
exists($S intersect $N)
The exists()
is redundant if used in a boolean context, eg you can write if($S intersect $N)
如果在布尔上下文中使用,
exists()
是多余的,例如你可以写if($S intersect $N)
(b) exists($S[. is $N])
(b)
exists($S[. is $N])
(Similarly, in a boolean context you can write if($S[. is $N])
(同样,在布尔上下文中,您可以编写
if($S[. is $N])
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