[英]PHP/MYSQL - Data retrieval
Going by the advice that join
are better than nested queries, I've converted all my nested queries to join
. 通过建议去join
比嵌套查询更好,我将我所有的嵌套查询到join
。 However, upon converting to join
, I'm unable to retrieve data into my array from the SQL result. 但是,在转换为join
,我无法从SQL结果检索数据到数组中。
Here are my queries : 这是我的查询:
Without join 没有加入
$a="SELECT F_DATE, COUNT(F_DATE) as COUNT_F
from FWH
where FI_NAME IN
(
SELECT I_NAME from INS_W WHERE INSTANCE_ID IN
(
SELECT I_MAP_ID FROM T_MAP where T_MAP_ID =
(
SELECT T_ID FROM TWY WHERE T_NAME = 'abc'
)
)
)
AND F_DATE between '$S_D' AND '$E_D'
GROUP BY F_DATE";
With join 与加入
$a="SELECT t1.F_DATE AS DATE_F, COUNT(t1.F_DATE) as COUNT_F
from FWH t1
JOIN INS_W t2 ON(t1.FI_NAME = t2.I_NAME)
JOIN T_MAP t3 ON(t2.INSTANCE_ID = t3.I_MAP_ID)
JOIN TWY t4 ON(t3.T_MAP_ID = t4.T_ID)
WHERE t4.T_NAME = 'abc' AND
t1.F_DATE BETWEEN '$S_D' AND 'E_D'GROUP BY t1.F_DATE";
Here's the PHP code to retrieve data 这是检索数据的PHP代码
$link = mysql_connect("ip", "user", "passs");
$dbcheck = mysql_select_db("db");
if ($dbcheck) {
$chart_array_1[] = "['F DATE','F COUNT']";
$result = mysql_query($a);
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
$f_date=$row["DATE_F"];
$f_count=$row["COUNT_F"];
$chart_array_1[]="['".$f_date."',".$f_count."]";
}
}
}
mysqli_close($link);
The SQL queries themselves run fine when tested directly on MySQL DB. 直接在MySQL DB上测试时,SQL查询本身运行良好。
For some reason, when I use joins, I'm forced to use row[0], row[1] etc instead of fetching values using the name of column. 出于某种原因,当我使用联接时,我被迫使用row [0],row [1]等,而不是使用column名称来获取值。 I do not understand the reason behind this. 我不明白其背后的原因。 However, this is the only way out in my case. 但是,这是我的唯一出路。 Code below for those who may get stuck in a similar situation as me. 下面的代码适用于可能陷入与我类似情况的人。
$link = mysql_connect("ip", "user", "passs");
$dbcheck = mysql_select_db("db");
if ($dbcheck) {
$chart_array_1[] = "['F DATE','F COUNT']";
$result = mysql_query($a);
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
$chart_array_1[]="['".$row[0]."',".$row[1]."]";
}
}
}
mysqli_close($link);
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