我怎样才能跳过输出结果

Question

I want to skip the number 10 so that i only have numbers from 15 to 5 without outputting number 10.

    <?php

    $x = 15;
    while($x >=5) {
    echo "$x <br>"; 
    $x--;
    } 

    ?>

Answer 1

<?php
    for($i=15;$i>=5;$i--){
       if($i == 10) continue;
       echo $i . '<br>';
    }
?>

or

<?php
    for($i=15;$i>=5;$i--){
       if($i != 10) echo $i . '<br>';
    }
?>

Answer 2

Add an if condition to ignore $x when it is equal to 10:

<?php

    $x = 15;
    while($x >=5 ) {
        if($x != 10) echo $x . "<br>"; 
        $x--;
    } 

?>`

Answer 3

All the other posts are correct, but since you're learning, you should really learn without using shorthand, as it can sometimes be difficult to read.

Not everyone uses shorthand, and in most practices a coding standard is used. Ours in particular doesn't use shorthand.

Example:

<?php

$x = 15;
while($x >=5 ) {
    if($x != 10){
        echo $x . "<br />"; 
    }
    $x--;
} 

?>

Answer 4

 $num = 15;
   while($num >=5 ) {
    if($num != 10) echo $num . "\n"; 
    $num--;
  } 

Answer 5

An other way without test:

$a = array_merge(range(15,11), range(9,5));

foreach($a as $num)
    echo $num . '<br>';