检查字符串的数字是否大于 1

Question

I have a method returning me a string that may contain numbers. I extract those numbers into a string with comma-separated value.

var stringOne = "Returned 12 string";
var extractNum = "1,2"

What I want now is to check this string against a regular expression that tests to see if the string has numbers greater than 1? I've tried few things but none seems to be working. Please suggest a way to accomplish it. Thanks in advance!

Answer 1

If you just want to test if your extract String containt numbers greater than 1, you can try below code

function check() {
        var str = "1,1,1,1,2,1,1";
        var patt = new RegExp("[2-9]");
        return patt.test(str); // true
    }

Answer 2

 var matched = "Returned 12 string".match(/[2-9]/g) if (matched !== null) { alert(matched.join(',')); } else { // No match }

Answer 3

You could do the following:

var extractNum = "1,2";
var hasGreaterThan1 = extractNum.split(',').some(function(val) { return val > 1; })

See documentation for Array.prototype.some

Answer 4

Ideally you would parse the number and use the actual numerical operators provided by Javascript to do this.

If you really must do it through a regular expression, you could use something like so: ^[2-9]|\\d{2,}$ . This will check that the number is either a single digit between 2 and 9 or else a digit made up from two or more numbers.

Answer 5

"ok" will be true if any number is bigger than 1;

var stringOne = "Returned 12 string";
var extractNum = "1,2"
var ok = haveNrBiggerThan1(extractNum);

function haveNrBiggerThan1(str){
    var nums = str.split(",");
    for(var i=0; i<nums.length; i++){var n=parseInt(nums[i]); if(n>1){return true;}}
    return false;
}

Answer 6

不使用正则表达式

extractNum.split(',').map(function(a){return parseInt(a)>1})