[英]Check query result with two column
Here is the table structure. 这是表格结构。
++++++++++++++++++++++++++++++++++++++++++++++
+ No + UniqueID + Email + Status +
+ 1 + 1q2w3e4r + myemail@gmail.com + NULL +
+ 2 + 12345qwe + myemail@yahoo.com + 1 +
++++++++++++++++++++++++++++++++++++++++++++++
The logic should be: 逻辑应为:
I want to input UniqueID
and Email
. 我想输入UniqueID
和Email
。 When I put the value is 1q2w3e4r
and Email
myemai@gmail.com
, it shoudl return True or put the uniqueID as response like this one below: $this->response(array('2' => $data['UniqueID'])); 当我将值设置为1q2w3e4r
并发送Email
myemai@gmail.com
,它应返回True或将uniqueID作为如下所示的响应:$ this-> response(array('2'=> $ data ['UniqueID'] ));
Same No.1 but it should return false, because i put UniqueID
that already has status = 1
. 相同的No.1,但它应该返回false,因为我放置了已经具有status = 1
UniqueID
。
Same As No.1 and 2, but this time i put the wrong uniqueID
. 与1号和2号相同,但是这次我输入了错误的uniqueID
。 eg. 例如。 uniqueID is 1234567. it shoud return false because uniqueID is not true. uniqueID为1234567。由于uniqueID不为true,因此应返回false。
And my code looks like this below: 我的代码如下所示:
========================================================================= Solve The Problem by modify this code below: ================================================== =======================通过修改以下代码来解决问题:
Model 模型
public function signup($data)
{
$this->db->select("status");
$this->db->from("mytable");
$this->db->where("UniqueID ", $data['UniqueID ']);
$this->db->where("email", $data['email']);
$q = $this->db->get();
return $q;
}
and my controller like this below: 和我的控制器如下所示:
if($result->num_rows() > 0) {
$s = $result->row()->status;
if (isset($s) && $s == 1)
{
$this->response(array('1' => 'missing data'));
} else if(!isset($s)){
$this->response(array('2' => $data['nopolis']));
}
} else {
$this->response(array('3' => 'missing'));
}
Kind of hard to understand you. 有点难以理解你。 But I believe you are looking for something like this. 但我相信您正在寻找类似的东西。 Try the following: 请尝试以下操作:
First, change your model method to this: 首先,将模型方法更改为:
public function signup($data){
$this->db->select("status");
$this->db->from("mytable");
$this->db->where("uniqueID", $data['uniqueID ']);
$this->db->where("email", $data['email']);
$q = $this->db->get();
return $q->row();
}
Then in your controller: 然后在您的控制器中:
public function validation_post(){
$data = array (
'uniqueID' => $this->input->get_post('nopolis')
);
$result = $this->signup->signup($data);
$s = $result->status;
if ($result) {
$s = $result->status;
if (isset($s) && $s == 1) {
//Condition where status = 1
} else if (!isset($s)) {
//Condition where status = NULL
} else {
//Condition where status is something else
}
} else {
//Condition where id and email does not exist
echo "No Results";
}
}
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