正则表达式提取由换行符分隔的两个字符串之间的字符串

Question

I have a string like below:

Movies(s):   
DIE ANOTHER DAY  
TOMORROW NEVER DIES  
WORLD IS NOT ENOUGH  
Running Date(s):  

I want to extract the movie names as separate matches not as a whole like below:

Match 1: DIE ANOTHER DAY  
Match 2: TOMORROW NEVER DIES  
Match 3: WORLD IS NOT ENOUGH  

I tried to use lookahead and lookbehind but couldn't succeed in getting three matches.

Answer 1

Here's a one-liner:

String[] movies = str.replaceAll(".*Movies\\(s\\):\\s*|Running Date\\(s\\):.*", "").split("[\n\r]+");

This code first strips off the front/back, leaving just the movie names, then splits on (platform independent) newline chars.

Answer 2

You can leverage the discard technique through a regex like this:

.*:|^(.+)$

Working demo

The idea behind the discard technique is to use a chain of pattern that you want to get rid off. So, you can have something like this:

discard patt1 | discard patt2 | discard pattN | (capture this)

Applying this technique to your string, you can modify above regex to something like this:

Movies\(s\):|Running Date\(s\):|(.+)
discard--^   discard--^  capture--^

Working demo

You can see easily with this diagram:

Match information

MATCH 1
1.  [11-26] `DIE ANOTHER DAY`
MATCH 2
1.  [27-46] `TOMORROW NEVER DIES`
MATCH 3
1.  [47-66] `WORLD IS NOT ENOUGH`

You can use this Java code:

Pattern regex = Pattern.compile(".*:|^(.+)$", Pattern.MULTILINE);
// or this line:
//     Pattern regex = Pattern.compile("Movies\\(s\\):|Running Date\\(s\\):|(.+)", Pattern.MULTILINE);
Matcher regexMatcher = regex.matcher("YOUR STRING HERE");
if (regexMatcher.find()) {
    System.out.println(regexMatcher.group(1));
} 

Answer 3

我通过使用以下正则表达式修复了它：

(?s)(?<=Movie\(s\)\:\s{0,3}\r{0,1}\n.{0,100})([A-Z \.]+)(?=.{0,100}Running\Date\(s\)\:)

Answer 4

String input = "Movies(s):\r\n" +
        "DIE ANOTHER DAY\r\n" +
        "TOMORROW NEVER DIES\r\n" +
        "WORLD IS NOT ENOUGH\r\n" +
        "Running Date(s):";

Pattern pattern = Pattern.compile("(([A-Z ]+)[\r\n]{1,2})");

Matcher m = pattern.matcher(input);

int index = 0;
while(m.find())
{
    System.out.println(++index + "," + m.group(2));
}

And the output will be(tested):

1,DIE ANOTHER DAY
2,TOMORROW NEVER DIES
3,WORLD IS NOT ENOUGH