如何从HttpPostedFileBase对象创建FileInfo对象？
[英]How do I create a FileInfo object from an HttpPostedFileBase object?
问题描述
I have a FileUpload control that passes the HttpPostedFileBase as a parameter into my controller. 
我有一个FileUpload控件，它将HttpPostedFileBase作为参数传递到我的控制器中。 Currently in the controller, I save the HttpPostedFileBase, and get the full path by hard coding it. 当前在控制器中，我保存了HttpPostedFileBase，并通过对其进行硬编码来获取完整路径。 I need a way to simply access the HttpPostedFileBase from the FileUpload control, and turn it into a FileInfo object WITHOUT saving it. 我需要一种方法，可以从FileUpload控件中简单地访问HttpPostedFileBase，并将其转换为FileInfo对象而不保存它。 I apologize if this is a dumb question, but I am still struggling to grasp the concept and differences of all of the different type of HttpPostedFileBase/FileInfo/etc. 如果这是一个愚蠢的问题，我深表歉意，但我仍在努力理解HttpPostedFileBase / FileInfo / etc等所有不同类型的概念和差异。 file "things". 文件“东西”。 I'd appreciate anyone's help! 我会感谢任何人的帮助！
1 个解决方案
解决方案1
1 2015-07-03 12:37:27
I made a comment about this and i decided to added as an answer. 我对此发表了评论，并决定添加为答案。
That's not possible. 那不可能 Fileinfo inherits from FileSystemInfo which can be a file or a directory(thats why DirectoryInfo exists). Fileinfo继承自FileSystemInfo ，后者可以是文件或目录（这就是DirectoryInfo存在的原因）。 So, its not possible to do it. 因此，不可能做到这一点。 You have to save the file in disk and load it with the path. 您必须将文件保存在磁盘中并使用路径加载。
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