[英]Get parameter Type from dynamic method using reflection
I've got this bit of code to get a setter method from a dynamic class.我有这段代码可以从动态类中获取 setter 方法。 But the parameters can be a
java.lang.String
or java.lang.Long
.但参数可以是
java.lang.String
或java.lang.Long
。 How can I dynamically get the parameter type?如何动态获取参数类型?
public Method getDynMethod(Class aClass, String methodName) {
Method m = null;
Class[] paramTypes = new Class[1];
paramTypes[0] = String.class;
try {
m = aClass.getMethod(methodName, paramTypes);
} catch (NoSuchMethodException nsme) {
nsme.printStackTrace();
}
return m;
}
This is the code that calls it这是调用它的代码
Class c = getDynClass(a.getAssetType().getDBTableName());
for (Long l : map.keySet()) {
AssetProperties ap = new AssetProperties();
ap.setAssetTypeProperties(em.find(AssetTypeProperty.class, l));
ap.setAssets(a);
ap.setValue(map.get(l));
a.getAssetProperties().add(ap);
String methodName = "set" + ap.getAssetTypeProperties().getDBColumn();
Method m = getDynMethod(c, methodName);
try {
String result = (String) m.invoke(c.newInstance(), ap.getValue());
System.out.println(result);
} catch (IllegalAccessException iae) {
iae.printStackTrace();
} catch (InvocationTargetException ite) {
ite.printStackTrace();
} catch (InstantiationException ie) {
ie.printStackTrace();
}
}
I could pass another parameter to the method but I still would not know what the parameter type would be我可以将另一个参数传递给该方法,但我仍然不知道参数类型是什么
You can get method's parameters types from method.getParameterTypes()
;您可以从
method.getParameterTypes()
获取方法的参数类型; ie: IE:
public Class[] methodsParamsTypes(Method method) {
return method.getParameterTypes();
}
see here for a complete example.有关完整示例,请参见此处。
Edit reading again your question now I'm unsure that the answer above is what you was looking.现在再次编辑阅读您的问题,我不确定上面的答案是否是您想要的。
Do you mean you have the parameter coming from a map in your code and you want to invoke the proper method by reflection?您的意思是您的代码中有来自地图的参数,并且您想通过反射调用正确的方法吗? Either the one with
Long
or String
?是
Long
还是String
? if so here is an example:如果是这样,这是一个例子:
public Method getDynMethod(Class aClass, String methodName, Object...params) {
Method m = null;
Class[] paramTypes = new Class[params.length];
for (int i = 0; i < paramTypes.length; i++) {
//note: if params[i] == null is not possible to retrieve the class type...
paramTypes[i] = params[i].getClass();
}
try {
m = aClass.getMethod(methodName, paramTypes);
} catch (NoSuchMethodException nsme) {
nsme.printStackTrace();
}
return m;
}
and in your code you can invoke it like that:在您的代码中,您可以像这样调用它:
Method m = getDynMethod(c, methodName, ap.getValue());
If you want to get the parameter type(s) of a method you should invoke the method called如果你想获得一个方法的参数类型,你应该调用被调用的方法
getParameterTypes() that returns an array of Class objects that are the parameter(s) expected.
getParameterTypes() 返回一个 Class 对象数组,这些对象是预期的参数。
Have a look here for more information: Method class Documentation在这里查看更多信息: 方法类文档
EDIT: I got ninja'ed :- (编辑:我被忍者 :- (
You could get all the methods, and filter by name like so:您可以获得所有方法,并按名称过滤,如下所示:
public Method getDynMethod(Class aClass, String methodName) {
for (Method m : aClass.getMethods()) {
if (methodName.equals(m.getName())) {
Class<?>[] params = m.getParameterTypes();
if (params.length == 1
&& (params[0] == Long.class || params[0] == String.class)) {
return m;
}
}
}
return null;
}
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