php / Javascript / Ajax加载内容不起作用
[英]php / Javascript / Ajax loading content does not work
问题描述
I'm trying to load content from a php file which name is "include.php" to a in another php file which name is "index.php". 
我正在尝试从名称为“ include.php”的php文件中的内容加载到名称为“ index.php”的另一个php文件中。 But the loading does not work. 但是加载不起作用。 The code is as below: 代码如下：
The file: index.php 文件：index.php
<header>
<script type="text/javascript">
function load(){
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
}else{
xmlhttp = new ActiveXObject('Microsoft.XMLHTTP');
}
xmlhttp.onreadystatechage = function (){
if(xmlhttp.readyState == 4 && xmlhttp.status == 200){
document.getElementById(adiv).innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open('GET', 'include.php', true);
xmlhttp.send();
}
</script>
</head>
<body>
<input type="submit" value="Submit" onclick="load();">
<div id="adiv"></div>
</body>
The File: include.php 文件：include.php
<?php
echo 'Hello!';
?>
Thanks. 谢谢。
3 个解决方案
解决方案1
1 2015-06-21 07:08:37
If what you are doing is the way you describe then this is simpler: 如果您正在做的是您描述的方式，那么这会更简单：
<header>
<?php include("include.php") ?>
</head>
<body>
<input type="submit" value="Submit" onclick="load();">
<div id="adiv"></div>
</body>
If you want to get result from include.php into JavaScript then you'll probably be better using ajax. 如果您希望将include.php结果获取到JavaScript中，那么使用Ajax可能会更好。
By the way, if you are planning a "universal header" for all your PHP files, you don't need to echo it just write it as normal HTML with any necessary PHP tags 顺便说一句，如果您正在为所有PHP文件计划一个“通用标头”，则无需回显它，只需将其写为带有任何必要PHP标记的普通HTML即可。
解决方案2
0 已采纳 2015-06-21 07:04:57
Should it not be document.getElementById("adiv").innerHTML = xmlhttp.responseText; 如果不是document.getElementById("adiv").innerHTML = xmlhttp.responseText; ? ？ Notice the quotes. 注意引号。
解决方案3
0 2015-06-21 07:12:57
....xmlhttp.onreadystatechage = function (){ if(xmlhttp.readyState == 4 && xmlhttp.st...
检查onReadyStateChange的拼写。
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