[英]XSLT Sequence Number Generation
I am preparing one flat file from XMl using XSLT 2.0.我正在使用 XSLT 2.0 从 XMl 准备一个平面文件。 My input XML is我的输入 XML 是
<city>
<family>
<parent>A</parent>
<child>A1</child>
</family>
<family>
<parent>A</parent>
<child>A2</child>
</family>
<family>
<parent>B</parent>
<child>B1</child>
</family>
<family>
<parent>B</parent>
<child>B2</child>
</family>
<family>
<parent>B</parent>
<child>B3</child>
</family>
<family>
<parent>C</parent>
<child>C1</child>
</family>
</city>
Expected Output
-----------------
01 A
02 B
03 C
I have to group parent and each parent has one entry in flat file and it should have correct sequence no.我必须对父项进行分组,并且每个父项在平面文件中都有一个条目,并且它应该具有正确的序列号。 I am not able to generate sequence no correcly.我无法正确地生成序列。
Assuming you use for-each-group
then outputting and formatting the position()
should suffice:假设您使用for-each-group
然后输出和格式化position()
就足够了:
<xsl:template match="/">
<xsl:for-each-group select="city/family" group-by="parent">
<xsl:value-of select="concat(format-number(position(), '00'), ' ', current-grouping-key(), ' ')"/>
</xsl:for-each-group>
</xsl:template>
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