如何解析XML文件

Question

I have a file in that format

<?xml version="1.0" encoding="UTF-8"?>
<AMG>
    <Include File="..."/> <!-- comment -->
    <Include File="...."/> <!-- comment -->

    <AMGmers Name="Auto">
        <Array Type="move" Name="move_name"/>
    </AMGmers>  

    <AMGmers Name="Black" Parent="Auto">
        <Attr Type="Color" Name="auto_Params"/>
    </AMGmers>
        <!-- comment -->

</AMG>

I have to get all name from <AMGmers> , and I have to check availability Parent. I was trying to do so

XmlDocument doc1 = new XmlDocument();
doc1.Load("test.xml");
XmlNodeList elemList1 = doc1.GetElementsByTagName("Name");

Please help me understand.

Answer 1

Since <AMG> is the root node and <AMGmers> tags are inside <AMG> , you can get all <AMGmers> tags using this syntax

XmlNodeList elemList1 = doc1.SelectNodes("AMG/AMGmers");

I assume you want to get the value of Name attribute from all <AMGmers> tags and check whether each <AMGmers> tag has Parent attribute, so this code should work

foreach (XmlNode node in elemList1)
{
    if (node.Attributes["Name"] != null)
    {
        string name = node.Attributes["Name"].Value;

        // do whatever you want with name
    }

    if (node.Attributes["Parent"] != null)
    {
        // logic when Parent attribute is present
        // node.Attributes["Parent"].Value is the value of Parent attribute
    }
    else
    {
        // logic when Parent attribute isn't present
    }
}

EDIT

If you want to get the <Array> nodes inside <AMGmers> , you can do so as below

foreach (XmlNode node in elemList1)
{
    XmlNodeList arrayNodes = node.SelectNodes("Array");
    foreach (XmlNode arrayNode in arrayNodes)
    {
        if (arrayNode.Attributes["Type"] != null)
        {
            // logic when Type attribute is present
            // arrayNode.Attributes["Type"].Value is the value of Type attribute
        }
    }
}

EDIT 2

If you want to enumerate all nodes inside <AMGmers> , you can do so as below

foreach (XmlNode node in elemList1)
{
    foreach (XmlNode childNode in node.ChildNodes)
    {
        // do whatever you want with childNode
    }
}