正则表达式提取JSON中的字符

Question

What would be the best regex to extract the following:

s = '":"1434919817660.wFzJl5KnFq1tyg5X0juKeQmbW8A="'
==> 14349198.17660.wFzJl5KnFq1tyg5X0.juKeQmbW8A=

It is a string between either a ' or " with length > 5 and that is terminated by ' or " . The best I could get was:

>>> re.search(r'''[\'|\"](.+)[\'+\"]''', x).group(1)
':"1434919817660.wFzJl5KnFq1tyg5X0juKeQmbW8A='

Answer 1

You can use re.sub

>>> re.sub(r'[":]', '', s)
'1434919817660.wFzJl5KnFq1tyg5X0juKeQmbW8A='

Answer 2

If you are going to replace use str.translate:

s = '":"1434919817660.wFzJl5KnFq1tyg5X0juKeQmbW8A="'

if len(s) > 5:
    print(s.translate(None,""":"'"""))
1434919817660.wFzJl5KnFq1tyg5X0juKeQmbW8A=

For python3 you need to create a mapping using the ord of the characters you want to replace:

s = '":"1434919817660.wFzJl5KnFq1tyg5X0juKeQmbW8A="'

print(s.translate({ord('"'):"",ord("'"):"",ord(":"):""}))

If you have json you could also extract by key, if it were json though you would not have any ' .

Answer 3

You could also try doing an string replace here:

s.replace('"','').replace(':','').replace("'",'').strip()
14349198.17660.wFzJl5KnFq1tyg5X0.juKeQmbW8A=