我将如何更改此正则表达式以在末尾接受0.5的单个十进制？

Question

I have the following regex:

/^(([0-2][0-9]{2}|3[0-5][0-9])|360)$/

This accepts numbers from 000-360. I also want it to accept the decimal .5 at the end. No other decimal should be accepted and it should also accept no decimal at all. Also 360.5 should not be accepted. How would I do this?

Answer 1

/^(([0-2][0-9]{2}|3[0-5][0-9])|360)(|\.5)$/

Answer 2

How about:

^((([0-2][0-9]{2}|3[0-5][0-9])(\.5)?)|360)$

https://regex101.com/r/gQ1vO6/2

Answer 3

在行尾之前的末尾添加(\\.5)* 。

Answer 4

Assuming 000 <= x <= 360 , but allowing for .5 values within that range:

^((?:[0-2][0-9]{2}|3[0-5][0-9])(?:\.5)?|360)$

I've added a non-capturing group to target 000 - 359 and added an optional .5 group after that.

^                                # Start of string
 (                               # Begin capture
  (?:[0-2][0-9]{2}|3[0-5][0-9])    # 000-359
  (?:\.5)?                         # (optional) .5 suffix
  |                              # -- OR --
  360                              # 360 (explicitly)
 )                               # End capture
$                                # End of string

This will also make the first capture group record whatever the number is.