[英]Reading only real contacts
I have a program which reads the contacts and then displays it into the ListView
. 我有一个程序,可以读取联系人,然后将其显示在
ListView
。 But the problem is that I have total 25k + contacts in my phone and 60% contacts are of google. 但是问题是我的手机中总共有25k +联系人,而Google中有60%的联系人。 So it takes too much time to read contacts.
因此,读取联系人需要太多时间。 How do I read contacts having phone number ?
如何阅读具有电话号码的联系人?
I'm using this code : 我正在使用此代码:
Cursor phones = as.getApplicationContext().getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,null,null, null);
while (phones.moveToNext())
{
String name=phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
}
phones.close();
Where clause can be used to filter the contacts with the phone numbers. where子句可用于过滤带有电话号码的联系人。 Use the below code to retrieve the contacts.
使用以下代码检索联系人。
CursorLoader cursorLoader = new CursorLoader(getActivity(), ContactsContract.Contacts.CONTENT_URI, new String[]{ContactsContract.Contacts._ID, ContactsContract.Contacts.DISPLAY_NAME},
ContactsContract.Contacts.HAS_PHONE_NUMBER + " > 0 ", null, ContactsContract.Contacts.DISPLAY_NAME + " COLLATE NOCASE ASC;");
For reading the contacts you need the following permission. 要阅读联系人,您需要具有以下权限。
<uses-permission android:name="android.permission.READ_CONTACTS" />
You can use HAS_PHONE_NUMBER. 您可以使用HAS_PHONE_NUMBER。 ContactsContract.Contacts.HAS_PHONE_NUMBER .
ContactsContract.Contacts.HAS_PHONE_NUMBER 。 An Example
一个例子
String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (hasPhone.equals(ContactsContract.Contacts.HAS_PHONE_NUMBER))
//do your thing
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