[英]Trying to parse XML and create a List information using Linq and C#
Very new to C# and Linq, lots to learn... I would like to be able to parse XML with Linq, and move a portion of the XML data into a List. 对于C#和Linq来说是非常新的东西,有很多东西要学习...我希望能够用Linq解析XML,并将XML数据的一部分移到List中。 The XML data is small, Initially (query 1 below) I was able to capture all nodes except the ACCT nodes.
XML数据很小,最初(下面的查询1)我能够捕获除ACCT节点之外的所有节点。 My 2nd attempt was to create a 2nd query (ACCT query below) but it only successfully captures the 1st occurrence of ACCT .
我的第二次尝试是创建第二次查询(下面的ACCT查询),但是它仅成功捕获了第一次出现的ACCT。 searched for some time, found several examples but I have not been successful in implementing way to capture all occurrences of ACCT with Linq and c#.
搜索了一段时间,发现了几个示例,但是我没有成功实现使用Linq和c#捕获所有出现的ACCT的方式。 Seems like a VERY useful tool, any assistance would be appreciated.
好像是一个非常有用的工具,将不胜感激。
here is XML 这是XML
<?xml version="1.0" encoding="utf-8"?>
<ORDER>
<EMPNUMBER>LDC</EMPNUMBER>
<ITEMNAME>NEWNAME_GR0045LDS01.JPG</ITEMNAME>
<DATETIMESTAMP>04-19-2015</DATETIMESTAMP>
<DEPT>HMES</DEPT>
<SHIPMENTLIST>
<ACCT>2222222222</ACCT>
<ACCT>1111111111</ACCT>
</SHIPMENTLIST>
</ORDER>
here is current class 这是当前班级
public class clsShipACCT
{
public string strShipACCT
{
get;
set;
}
}
here is logic(commented out items show failed attempts list) 这是逻辑(注释掉的项目显示失败尝试列表)
//this gets all xml details except account(ACCT)
var query1 = from item in xDoc.Descendants("ORDER") // xDoc.Elements() //xDoc.Descendants("ORDER") // xDoc.Root.Elements("ORDER")
select new
{
EmpNum = item.Element("EMPNUMBER").Value,
ItemName = item.Element("ITEMNAME").Value,
OrderDate = Convert.ToDateTime(item.Element("DATETIMESTAMP").Value),
};
//attempt to get ACCT detail
var Acctlist = from P in xDoc.Root.Descendants("SHIPMENTLIST")
select new { b = P.Element("ACCT").Value };
foreach(var p in ACCTlist)
ACCTgram.WriteLog("Parsed XML Acct: " + p);
//failed attempt to capture ACCT in list:
// List<clShipACCT> testList = ACCTlist.ToList<clShipACCT>();
//////var ACCTlist = (from P in xDoc.Descendants("SHIPMENTLIST")
////// select new clShipACCT { strShipACCT = childitem.Element("ACCT").Value }).ToList();
//////testShipACCTList.AddRange(ACCTlist);
Use .Elements
method - this method return all elements with given name 使用
.Elements
方法-此方法返回具有给定名称的所有元素
.Element
method will return only first element .Element
方法将仅返回第一个元素
var shipments = xDoc.Root.Descendants("SHIPMENTLIST")
List<String> acctList = new List<String>();
foreach(var accts in shipments)
{
acctList.AddRange(accts.Elements("ACCT").Select(acct => acct.Value));
}
foreach(string acct in acctlist)
ACCTgram.WriteLog("Parsed XML Acct: " + acct);
var result = xDoc.Root.Element("SHIPMENTLIST").Elements("ACCT").Select(x => x.Value).ToList();
Using the xml in the post, this should yield a 在帖子中使用xml,这应该会产生一个
List<string>
of the values in the ACCT fields. ACCT字段中的值。
You are very close, just add your accounts search to your first query and generic object creation. 您非常接近,只需将帐户搜索添加到第一个查询和通用对象创建中即可。
Change this to be: 更改为:
var query1 = from item in xDoc.Descendants("ORDER") // xDoc.Elements() //xDoc.Descendants("ORDER") // xDoc.Root.Elements("ORDER")
select new
{
EmpNum = item.Element("EMPNUMBER").Value,
ItemName = item.Element("ITEMNAME").Value,
OrderDate = Convert.ToDateTime(item.Element("DATETIMESTAMP").Value),
Accts = item.Element("SHIPMENTLIST").Elements("ACCT").Select(x => x.Value).ToList()
};
//this works in LinqPad...Elements() return multiple instances... //这适用于LinqPad ... Elements()返回多个实例...
void Main()
{
XDocument doc= XDocument.Load(@"d:\test2.xml");
var orders = doc.Root.Elements("ORDER")
.Select (o => new Order
{
EmpNumber=o.Element("EMPNUMBER").Value,
ItemName=o.Element("ITEMNAME").Value,
TimeStamp=o.Element("DATETIMESTAMP").Value,
Shipments=o.Element("SHIPMENTLIST").Elements("ACCT").Select (e => new Shipment{Account= e.Value}).ToList()
}
);
orders.Dump();
}
class Order
{
public Order ()
{
this.Shipments=new List<Shipment>();
}
public string EmpNumber { get; set; }
public string ItemName { get; set; }
public string TimeStamp { get; set; } //should be date time
public string Department { get; set; }
public List<Shipment> Shipments { get; set; }
}
class Shipment
{
public string Account { get; set; }
}
I assumed the following xml: added ORDERS as the root element since one order in xml is really trivial... 我假设使用以下xml:将ORDERS添加为根元素,因为xml中的一个订单确实很简单。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.