python findall找不到正则表达式

Question

So I have a string: data = "1234 5678 9012 3456" and I have regex: (\\S)+ Which I confirmed matches "1234", "5678", "9012", "3456" with RegExr.

However when I do: re.findall("(\\S)+", data) it returns ["4", "8", "2", "6"] . Am I using re.findall incorrectly to find "1234", "5678", "9012", "3456" ?

Answer 1

The capturing group caused this:

re.findall("\S+", data)

works as expected.

Answer 2

No your regex is incorrect :

>>> re.findall("\S+", data)
['1234', '5678', '9012', '3456']