[英]build a tree json for jqtree from data
I am trying to create the tree json for the following data that builds a jqtree 我正在尝试为以下构建jqtree的数据创建树json
var data = [
{
"director": "Name1",
"name": "sub-sub-child1",
"teamname": "sub-child1",
"teamManager": "child1"
},
{
"director": "Name1",
"name": "sub-sub-child2",
"teamname": "sub-child1",
"teamManager": "child1"
},
{
"director": "Name1",
"name": "sub-sub-child2",
"teamname": "sub-child2",
"teamManager": "child2"
},
{
"director": "Name2",
"name": "sub-sub-child1",
"teamname": "sub-child1",
"teamManager": "child1"
},
{
"director": "Name2",
"name": "sub-sub-child2",
"teamname": "sub-child2",
"teamManager": "child2"
},
{
"director": "Name3",
"name": "sub-sub-child1",
"teamname": "sub-child1",
"teamManager": "child1"
},
{
"director": "Name3",
"name": "sub-sub-child2",
"teamname": "sub-child2",
"teamManager": "child2"
}
];
console.log(data);
var aNode = [];
var aTempNode = [];
$.each(data, function(index, value) {
//console.log(value);
var key = {};
if($.inArray(value.director, aTempNode) == -1) {
aTempNode.push(value.director);
key['label'] = value.director;
key['children'] = [{label: value.teamManager, children: [{label: value.teamname, children: [{label: value.name}]}]}];
aNode.push(key);
} else {
//console.log(aNode)
if(key['teamname'] == aNode.children) {
}
}
});
console.log(aNode);
EDIT2 EDIT2
The tree should be in this form 树应该是这种形式
Name1
|
|___child1
| |
| |___sub-child1
| | |
| | |___sub-sub-child1
| | |___sub-sub-child2
| |
| |___sub-child2
| |
| |___sub-sub-child1
| |___sub-sub-child2
|
|____child2
Edit1 EDIT1
I'm half way through it. 我已经完成了一半。 I'm confused how to proceed from here. 我很困惑如何从这里开始。 fiddle 小提琴
Try this, You will get what you need in "temp" variable 尝试一下,您将在“临时”变量中获得所需的内容
var temp = []; $.each(data, function(row, val) { var director = $.grep(temp, function(v) { return v.label == val.director }); if (director.length) { var teamManager = $.grep(director[0].children, function(v) { return v.label == val.teamManager }) if (teamManager.length) { var teamname = $.grep(teamManager[0].children, function(v) { return v.label == val.teamname }) if (teamname.length) { var name = $.grep(teamname[0].children, function(v) { return v.label == val.name }) if (!name.length) { teamname[0].children.push({ label: val.name, children: [] }); } } else { teamManager[0].children.push({ label: val.teamname, children: [{ label: val.name, children: [] }] }); } } else { director[0].children.push({ label: val.teamManager, children: [{ label: val.teamname, children: [{ label: val.name, children: [] }] }] }) } } else { temp.push({ label: val.director, children: [{ label: val.teamManager, children: [{ label: val.teamname, children: [{ label: val.name, children: [] }] }] }] }); } });
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