在批处理文件中用％替换特殊字符

Question

Can anyone help how to replace a string which contains special character like space,(,-,) etc. Lets say i have a string:

str=A Room Has (1 level) - (2 - leve) Rooms

Output string should be like:

str=A%Room%Has%%1%level%%%%2%%%leve%%Rooms

Answer 1

This should work:

set "str=A Room Has (1 level) - (2 - leve) Rooms"
set "str=!str:-=%%!"
set "str=!str:(=%%!"
set "str=!str:)=%%!"
set "str=!str: =%%!"

Answer 2

Try like this :

@echo off
set "str=A Room Has (1 level) - (2 - leve) Rooms"
echo Before string substitution :   %str%
pause
setlocal EnableDelayedExpansion
set "str=!str:-=%%!"
set "str=!str:(=%%!"
set "str=!str:)=%%!"
set "str=!str: =%%!"
Color 0A
echo After string substitution  :   !str!
pause