在动态字符串中，如何在特定字符处开始子字符串并在特定字符处结束子字符串？
[英]In a dynamic string, how to start a substring at a certain character and end it at certain character?
问题描述
I have string in javascript. 
我在javascript中有字串。
var string = "BLAH BLAH BLAH width: 673px; height: 123px; BLAH BLAH BLAH width: 1009px; height: 237px; BLAH BLAH"
I want to have two substrings come out of this. 我想从中得到两个子串。 One that starts at 'width' and end at 'px' and one that starts at 'height' and ends at 'px' . 一个以'width'开头并以'px'结尾，另一个以'height'开头并以'px'结尾。
This will happened for each pair of 'width' and 'height' . 每对'width'和'height'都会发生这种情况。 This can appear n amount of times in my string. 这可能在我的字符串中出现n次。 Each time with different numbers for width and height. 每次用不同的数字表示宽度和高度。
I really don't know how to go about this since the string is dynamic in length. 我真的不知道该怎么做，因为字符串的长度是动态的。 I can't just start a substring or substr at a certain index and go to a certain index. 我不能只是在某个索引处开始一个substring或substr并转到某个索引。 I don't see how I could use a split and join either. 我看不到如何使用split和join 。 Is there anyway to do this with jQuery or javascript. 无论如何，使用jQuery或javascript可以做到这一点。
my current way is very slow... 我目前的方式很慢...
for (var w = 1; w <= 10000; w++) {
for(var h = 1; h<=10000; h++)
{
var match = text.match("style=\"width: " + w + "px; height: " + h + "px;");
if (match != null) {
text = text.split("style=\"width: " + w + "px; height: " + h + "px;").join('');
}
}
}
After the substrings are found I want them to be removed from my string. 找到子字符串后，我希望将其从我的字符串中删除。
3 个解决方案
解决方案1
2 已采纳 2015-06-24 19:41:24
After edits, you can simply do this for your requirements: 编辑后，您可以根据需要简单地执行此操作：
var string = "BLAH BLAH BLAH width: 673px; height: 123px; BLAH BLAH BLAH width: 1009px; height: 237px; BLAH BLAH";
var regExp = /(\b\w+:[^:]*px)/g
string = string.replace(regExp,'')
With regex, you can do like this: 使用正则表达式，您可以这样：
var string = "BLAH BLAH BLAH width: 673px; height: 123px; BLAH BLAH BLAH width: 1009px; height: 237px; BLAH BLAH";
var regExp = /(\b\w+:[^:]*px)/g
var match = regExp.exec(string);
while(match != null)
{
var width = match[1]
match = regExp.exec(string);
var height = match[1]
match = regExp.exec(string);
}
After this, In each iteration, the variable width will have the substring width: 4874px and the variable height will have the substring height: 898px 此后，在每次迭代中，变量width将具有子字符串width: 4874px ，变量height将具有子字符串height: 898px
解决方案2
2 2015-06-24 21:15:02
An elegant way to extract string between two others is to add a function to String object. 提取其他两个字符串之间的一种优雅方法是向String对象添加一个函数。
/** * Extract a string between a Prefix and a Suffix * * @param prefix {string} Prefix string * @param suffix {string} Suffix string * @param trimSpace {boolean} (optional default false) is string space trimmed * @returns {string} String between prefix and suffix */ String.prototype.between = function(prefix, suffix, trimSpace) { trimSpace = typeof trimSpace !== 'undefined' ? trimSpace : false; var thisString = this; var index = thisString.indexOf(prefix); if (index >= 0) { thisString = thisString.substring(index + prefix.length); } else { return ""; } if (suffix) { index = thisString.indexOf(suffix); if (index < 0) { return ""; } else { thisString = thisString.substring(0, index); } } return trimSpace ? thisString.trim() : thisString; } var theString = "*Other text that is dynamic in length* width: 4874px; height: 898px *more dynamic length text*" var width = theString.between("width:", "px"); var widthTrimmed = theString.between("width:", "px", true); var heightTrimmed = theString.between("height:", "px", true); document.write("Not trimmed width: width=>" + width + "<" + "<br/>"); document.write("Trimmed width: widthTrimmed=>" + widthTrimmed + "<" + "<br/>"); document.write("Trimmed height: heightTrimmed=>" + heightTrimmed + "<" + "<br/>");
<body></body>
解决方案3
1 2015-06-24 19:36:55
Assuming the format remains the same getting the index of width/height and px should be enough 假设格式保持不变，则获取宽度/高度和px的索引应该足够
var string = "*Other text that is dynamic in length* width: 4874px; height: 898px; *more dynamic length text*"; var windexStart=string.indexOf('width')+6; var windexStop=string.indexOf('px;'); var hindexStart=string.indexOf('height')+7; var hindexStop=string.lastIndexOf('px;'); var width=string.substring(windexStart,windexStop); var height=string.substring(hindexStart,hindexStop); alert(width+' '+height);
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