[英]Swagger ui url with parameters
How to pass base url in the form http://localhost:3000/resources/api/?key=aslkdajd1323121lklakskdl
to swagger ui ? 如何将基本URL以
http://localhost:3000/resources/api/?key=aslkdajd1323121lklakskdl
给swagger ui?
I was able to access http://localhost:3000/resources/api
but when I add auth filter and pass key, it says, Unauthorized
. 我能够访问
http://localhost:3000/resources/api
但是当我添加auth过滤器并传递密钥时,它说, Unauthorized
。
Using swagger 1.X 使用swagger 1.X
Pre-populating the parameter through apiKeyauthorization in index.html did not help, but when I type in the key in UI, it worked. 通过index.html中的apiKeyauthorization预先填充参数没有帮助,但是当我在UI中键入键时,它起作用了。 Unable to understand the reason for this.
无法理解其原因。 Hope someone can help me make sense out of it.
希望有人可以帮助我理解它。
Try this swagger 2.0 file (use http://studio.restlet.com to downgrade to version 1.2) : 试试这个swagger 2.0文件(使用http://studio.restlet.com降级到1.2版):
{
"swagger": "2.0",
"info": {
"version": "0.0.1",
"title": "Todo App"
},
"host": "localhost:3000",
"schemes": [
"http"
],
"paths": {
"/resources/api": {
"post": {
"parameters": [
{
"name": "key",
"in": "query",
"description": "key",
"required": true,
"type": "string"
}
],
"responses": {
"200": {
"description": "Successful response"
}
}
}
}
}
}
I was able to solve this by adding window.authorizations.add("key", new ApiKeyAuthorization("key", yourKeyValue, "query"));
我能够通过添加
window.authorizations.add("key", new ApiKeyAuthorization("key", yourKeyValue, "query"));
来解决这个问题window.authorizations.add("key", new ApiKeyAuthorization("key", yourKeyValue, "query"));
in the SwaggerUI constructor function window.swaggerUi = new SwaggerUi({ . . .
在SwaggerUI构造函数
window.swaggerUi = new SwaggerUi({ . . .
right before the statement window.swaggerUi.load()
就在语句
window.swaggerUi.load()
You just need get the parameter from the url with javscript. 您只需要使用javscript从url获取参数。 In the file "index.html", under swagger-ui/dist folder, add something like this to get your key:
在文件“index.html”中,在swagger-ui / dist文件夹下,添加这样的内容以获取密钥:
var key = window.location.search.match(/key=([^&]+)/);
You can see a simple example in my GIST . 你可以在我的GIST中看到一个简单的例子。
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