Python：如何为 XML 文档生成唯一标识符？

Question

XSLT has a generate-id( xml-document ) function. With it I can create a unique identifier for an XML document.

In Python how would I generate a unique identifier for an XML document?

Note: the unique identifier should be based on the content of the XML document, not the file name of the XML document. For example, this XML document

<root>
   <comment>Hello, World</comment>
</root>

and this XML document

<document>
   <test>Blah, Blah</test>
</document>

must generate different identifiers, even if their file names are identical.

I have a graph of XML documents. So I need some way to recognize, "Hey, I've already seen this XML document." I don't want to compare entire XML documents. Instead, I want to compare UUIDs that correspond to the XML.

Answer 1

A colleague just sent me the answer:

For mapping text to an ID, we've used MD5 as one hash digest. Give the md5() function an XML document (string) and it will return a 32-character identifier.

More details:

---

genid.py

import sys
import stdio
from hashlib import md5

def digest_md5(obj):
    if type(obj) is unicode:
        obj = obj.encode('utf8')
    return md5(obj).hexdigest()

s = sys.stdin.readline()
stdio.writeln(digest_md5(s))

Then I turned it into an exe file.

Then from a DOS command prompt I typed this command:

type input.txt | genid

where input.txt is:

<Document>Hello, World</Document>

And I got this output:

df6f8283335bf3f657a89733e3d36b84

Beautiful!

Answer 2

import uuid
unique_id = uuid.uuid1()

You can also generate hexadecimal id or integer id by

uuid.uuid1().hex    # For hexadecimal id
uuid.uuid1().int    # For integer id

Answer 3

import uuid

#Create unique filename
uid = uuid.uuid1() # Generate UUID
uidstr = str(uid.int)[:21]
clientoneID = "8888"
OrderID = (clientoneID + uidstr)

#Save unique xmlfile
xmlf = open(OrderID, 'w')
xmlf.write(xmlfile)#Content of your XML file
xmlf.close