JSONArray中的JSONObject

Question

I'm trying to put a JSONObject inside a JSONArray in Java. Here is my two objects:

JSONArray:

[{
    "url": null,
    "flag": "0",
    "read": "0",
    "time": 2000,
    "exp": null,
    "population": 10
}]

JSONObject:

{
"events": [
    {
        "color": "Green",
        "event": "Restart"
    },
    {
        "color": "Black",
        "event": "Shutdown"
    },
    {
        "color": "White",
        "event": "Read"
    }       
]
}

Expected result:

[
{
    "url": null,
    "flag": "0",
    "read": "0",
    "time": 2000,
    "exp": null,
    "population": 10,
    "events": [
        {
            "color": "Green",
            "event": "Restart"
        },
        {
            "color": "Black",
            "event": "Shutdown"
        },
        {
            "color": "White",
            "event": "Read"
        }
    ]
}
]

I tried to use this code, but the result is not ok:

jsonArray.put(jsonObject);

Unexpected result:

[
{
    "url": null,
    "flag": "0",
    "read": "0",
    "time": 2000,
    "exp": null,
    "population": 10
},
{
    "events": [
        {
            "color": "Green",
            "event": "Restart"
        },
        {
            "color": "Black",
            "event": "Shutdown"
        },
        {
            "color": "White",
            "event": "Read"
        }
    ]
}
]

The "events" key-value most be inside the unique element in JSONArray, not as another element.

Answer 1

The JSONArray contains one JSONObject . When you jsonArray.put(jsonObject); you are adding it to the JSONArray , not to the JSONObject in the JSONArray .

This will add the jsonObject to the first JSONObject in your JSONArray

jsonArray.getJsonObject(0).put("events",jsonObject.get("events"));

Answer 2

You need,

((JSONObject) jsonArray.get(0)).put("events", jsonObject.get("events"));

Or, in a more generalized form,

    for (Map.Entry entry : (Set<Map.Entry>) jsonObject.entrySet()) {
        ((JSONObject) jsonArray.get(0)).put(entry.getKey(), entry.getValue());
    }

Answer 3

I did not tested the code but I think this would work. Try it if you want. jsonArray[0].events will create a new field named 'events' in the 0 indexed Object.

 jsonArray[0].events = jsonObject.events;