匹配正则表达式-JavaScript

Question

So I have the following url:

var oURL = "https://graph.facebook.com/#{username}/posts?access_token=#{token}";

I want to take username and token out of it;

I tried:

var match = (/#\{(.*?)\}/g.exec(oURL));
console.log(match);

but it is giving me:

["#{username}", "username", index: 27, input: "https://graph.facebook.com/#{username}/posts?access_token=#{token}"

Why isn't catching token?

Thanks

Answer 1

The problem is that exec only returns the first match from the given index whenever called.

Returns

If the match succeeds, the exec() method returns an array and updates properties of the regular expression object. The returned array has the matched text as the first item, and then one item for each capturing parenthesis that matched containing the text that was captured.

If the match fails, the exec() method returns null.

You would need to loop, continuously matching again to find all the matches.

 var matches = [], match, regex = /#\\{(.*?)\\}/g, oURL = "https://graph.facebook.com/#{username}/posts?access_token=#{token}"; while (match = regex.exec(oURL)) { matches.push(match) } console.log(matches) 

However, if you are only interested in the first capture group, you can only add those to the matches array:

 var matches = [], match, regex = /#\\{(.*?)\\}/g, oURL = "https://graph.facebook.com/#{username}/posts?access_token=#{token}"; while (match = regex.exec(oURL)) { matches.push(match[1]) } console.log(matches) 

Answer 2

尝试以下方法：

oURL.match(/#\\{(.*?)\\}/g)

Answer 3

The answer you accepted is perfect, but I thought I'd also add that it's pretty easy to create a little helper function like this:

function getMatches(str, expr) {
  var matches = [];
  var match;
  while (match = expr.exec(str)) {
    matches.push(match[1]);
  }
  return matches;
}

Then you can use it a little more intuitively.

var oURL = "https://graph.facebook.com/#{username}/posts?access_token=#{token}";
var expr = /#\{([^\{]*)?\}/g;
var result = getMatches(oURL, expr);
console.log(result);

http://codepen.io/Chevex/pen/VLyaeG

Answer 4

尝试这个：

var match = (/#\{(.*?)\}.*?#\{(.*?)\}/g.exec(oURL));