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浮点数组未转换为 int:Python

[英]Float Array is not converted to int: Python

I have a float numpy array x, which contains values like, 0, .5, 1, 1.5,etc.我有一个 float numpy 数组 x,其中包含 0、.5、1、1.5 等值。 I want to convert the float values into integers based on some equation and store them in a new array, newx.我想根据某个方程将浮点值转换为整数,并将它们存储在一个新数组 newx 中。 I did this,我这样做了,

newx=np.zeros(x.shape[0])
    for i in range (x.shape [0]):
        newx[i]=  ((2*x[i]) +1)
    print(newx, v)

However, when printing xnew, I get values like但是,在打印 xnew 时,我得到的值如下

(array([   1.,    2.,    3.,    4.,    5.,    6.,    7.,    8.,    9.,
         10.,   11.,   12.,   13.,   14.,   15.,   16.,   17.,   18.])

newx must be used in some process, and it must be integer, when I want to use it in that process, I get an error stating that it must be of integer or Boolean type. newx 必须在某个进程中使用,并且它必须是整数,当我想在该进程中使用它时,我收到一个错误,指出它必须是整数或布尔类型。 Can anyone please tell me what mistake I've done?谁能告诉我我犯了什么错误?

Thank You.谢谢你。

Numpy is specifically designed for array manipulation. Numpy 专为数组操作而设计。 Try not to iterate over a numpy array like you did.尽量不要像你那样迭代一个 numpy 数组。 You can read about how numpy datatypes are a little different than inbuilt datatypes.您可以阅读有关 numpy 数据类型与内置数据类型有何不同的信息。 This leads to much higher run times.这会导致更长的运行时间。

Anyways Here is a working code for your problem无论如何这是您的问题的工作代码

newx=x*2+1
newx=numpy.int16(newx)      # as easy as this. ;)

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