美国电话从字母到数字的转换

Question

Think I have gone wrong somewhere so I could use some help. OK the idea is to have the letters you usually find on phones. eg if I wanted to find the number for HAIRCUT it should output like 4247288.

public class PhoneNumber
{
    String s;
    int i;

    private void PhoneNumber()
    { 
      if ("ABC".contains(""+s.charAt(i))){
          i=2;
        }
          else if ("DEF".contains(""+s.charAt(i))){
              i=3;
            }
            else if ("GHI".contains(""+s.charAt(i))){
                i=4;
            }
            else if ("JKL".contains(""+s.charAt(i))){
                 i=5;
            }
            else if ("MNO".contains(""+s.charAt(i))){
                i=6;
            }
            else if ("PQRS".contains(""+s.charAt(i))){
                i=7;
            }
            else if ("TUV".contains(""+s.charAt(i))){
                i=8;
            }
            else if ("WXYZ".contains(""+s.charAt(i))){
                i=9;
            }                     
    }
    public void decode(){
        PhoneNumber pn = new PhoneNumber();
        pn.decode("HAIRCUT")
        pn.decode("NEWCARS"); 
    }
   }

I know i am missing stuff and even the println at the end but need guidance on how to do this. if you look at the code ABC will come out as 2, DEF as 3 etc. Any ideas? I'm very new to Java apologies in advance for my failed attempt.

Answer 1

I'd write it like this:

for (int i=0; i< line.length(); i++){
   convert(line.charAt(i));
}


private static int convert(char c){
    int answer;
    switch(c){
        case 'A': 
        case 'B': 
        case 'C':
            answer = 2;
            break;
        case 'D':
        case 'E':
        case 'F':
            answer = 3;
            break;
        ....
    }
    return answer;
}

Answer 2

I would solve it like this:

private static String digits = "22233344455566677778889999";

public static String convert(String input) {
    char[] chars = input.toCharArray();
    for(int i=0; i<chars.length; i++) {
        if(chars[i] >= 'A' && chars[i] <= 'Z')
            chars[i] = digits.charAt(chars[i]-'A');
    }
    return new String(chars);
}

The digits string is actually a mapping between letters from 'A' to 'Z' into digits (first symbol in it corresponds to 'A', second to 'B' and so on).