[英]Parsing hex values with Boost Spirit
I have been playing around with parsing with Boost Spirit and was wondering if anyone could help me get this to work. 我一直在与Boost Spirit进行解析,并且想知道是否有人可以帮助我使其正常工作。 I have a simple parser that takes a file containing a pair of entries on each line.
我有一个简单的解析器,该解析器接受一个文件,每行包含一对条目。 Something similar to the following:
类似于以下内容:
Foo 04B
Bar 1CE
Bam 456
My code below currently parses this out and places each pair into a std::map and it seems to work correctly. 我下面的代码目前对此进行了解析,并将每对放入std :: map中,并且似乎可以正常工作。 What I really want to do is parse out the second string on each line and convert it to an integer.
我真正想做的是解析每一行的第二个字符串,并将其转换为整数。 I have looked at int_parser and how you can specify the base but have been unable to get a similar setup to compile.
我看过int_parser以及如何指定基数,但无法获得类似的设置来进行编译。
namespace qi = boost::spirit::qi;
std::map<std::string, std::string> results;
void insert(std::pair<std::string, std::string> p) {
results[p.first] = p.second;
}
template <typename Iterator>
bool parse_numbers(Iterator first, Iterator last) {
using qi::char_;
using qi::parse;
qi::rule<Iterator, std::pair<std::string, std::string>()> assignment;
assignment = +(~char_(' ')) >> +(char_);
bool r = parse(
first,
last,
assignment[&insert]);
if (first != last)
return false;
return r;
}
int main(int argc, char* argv[]) {
std::ifstream ifs;
std::string str;
ifs.open (argv[1], std::ifstream::in);
while (getline(ifs, str)) {
if (!parse_numbers(str.begin(), str.end())) {
std::cout << "Parsing failed\n";
}
}
return 0;
}
What I would really like if to parse it out directly as a std::pair <std::string, int
>. 我真正想将其解析为std :: pair
<std::string, int
>的内容。 Any help is appreciated. 任何帮助表示赞赏。
More information: 更多信息:
I was trying to declare a parser similar to this one: uint_parser<unsigned, 16> hex_value;
我试图声明一个与此类似的解析器:
uint_parser<unsigned, 16> hex_value;
and then I was trying to replace the +(char_) in my rule to +(hex_value). 然后我尝试将规则中的+(char_)替换为+(hex_value)。
I'm a little confused with everything complicated going on there (especially the semantic action [&insert]
which seems to gratuitously use a global variable). 我对那里发生的一切复杂情况感到有些困惑(尤其是语义动作
[&insert]
似乎无意中使用了全局变量)。
See Boost Spirit: "Semantic actions are evil"?
参见Boost Spirit:“语义行为是邪恶的”? if you're interested in my stance on premature use of semantic actions.
如果您对我过早使用语义动作的立场感兴趣。
In this case you could just use Boost Fusion adaptation of std::pair<>
在这种情况下,您可以只使用Boost Fusion修改
std::pair<>
#include <boost/fusion/adapted/std_pair.hpp>
and now you can simply assign directly into a map: 现在您可以直接将其直接分配到地图中:
std::map<std::string, int> results;
if (ifs >> qi::phrase_match(
(qi::lexeme[+qi::graph] >> qi::int_parser<int, 16>{}) % qi::eol,
qi::blank, results)
)
As you surmised I 你猜我
int_parser<int,16>
int_parser<int,16>
std::cin
for simplicity ( NOTE you didn't check argc
...) std::cin
( 注意,您没有检查argc
...) phrase_match
as a nice way to parse from input stream iterators implicitly phrase_match
作为从输入流迭代器隐式解析的好方法 #include <boost/fusion/adapted/std_pair.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/qi_match.hpp>
#include <map>
namespace qi = boost::spirit::qi;
int main() {
std::cin.unsetf(std::ios::skipws);
std::map<std::string, int> results;
if (std::cin >> qi::phrase_match(
(qi::lexeme[+qi::graph] >> qi::int_parser<int, 16>{}) % qi::eol,
qi::blank, results)
)
{
std::cout << "Parse success:\n";
for(auto& entry : results)
std::cout << "'" << entry.first << "' -> " << entry.second << "\n";
} else {
std::cout << "Parse failed\n";
}
}
Output: 输出:
Parse success:
'Bam' -> 1110
'Bar' -> 462
'Foo' -> 75
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