如何在python的请求库中使用变量

Question

I'm trying to make a script which reads crunchyroll's rss and visits the LINK in the latest upload and downloads subs from it.. the process goes like : 1.) Read The latest episode link from RSS. 2.) Go to the link 3.) In the source code, look for text "ssid". 4.) Get the 6 characters of the ssid. 5.) Then append those characters at the end of this like " http://www.crunchyroll.com/xml/?req=RpcApiSubtitle_GetXml&subtitle_script_id= " and save the xml page.

My script works half way...

My Code:-

import feedparser
import webbrowser
import os
import subprocess  
import re
import urllib
import urllib2
from urllib2 import urlopen
from bs4 import BeautifulSoup
import requests
import cookielib


feed = feedparser.parse('http://www.crunchyroll.com/rss/anime')  #checks the RSS
url = feed['entries'][0]['link'] + '?p720=1'         # get's the link from latest release and appends some character for the 720p resolution of the link.

# Now, here, I'm writing this URL to a text file and then read from the text file

file = open("newfile.txt", "w")
file.write(url)
file.close()

file = open('newfile.txt', 'r')
#print file.read()
lobo = file.read()
print lobo

# Now, I put the URL that is being read from file in requests to go to the link. Everything works fine till here.

r = requests.get(lobo)
soup = BeautifulSoup(r.text)
print soup.title
webbrowser.open_new_tab(lobo)
subtitles = soup.findAll('span',{'class':'showmedia-subtitle-text'})
for ssid in subtitles:
  x = ssid.find_all('a', limit=1)
for a in x:
  print a['href'][-6:]

xmlLink = 'http://www.crunchyroll.com/xml/?req=RpcApiSubtitle_GetXml&subtitle_script_id=' + a['href'][-6:]
#webbrowser.open_new_tab(xmlLink)
print xmlLink

Now, I get error that 'a' in this xmlLink is not defined.

But, there's a twist to it... if I put the direct http link in "r = requests.get(lobo)" .. everything works like it is supposed to.But, if I use this variable.. it's not working.

Any help would be appreciated.Thank You

Answer 1

It looks like the a variable is defined inside of the for loop but the xmlLink variable is not. Try indenting the xmlLink line in to match the indentation level of the for loop. For example:

for a in x:
  print a['href'][-6:]

  xmlLink = 'http://www.crunchyroll.com/xml/?req=RpcApiSubtitle_GetXml&subtitle_script_id=' + a['href'][-6:]
  #webbrowser.open_new_tab(xmlLink)
  print xmlLink

Answer 2

The url that you're using is a str . You should use Python's string format function.

xmlLinkBase = 'http://www.crunchyroll.com/xml/?req=RpcApiSubtitle_GetXml&subtitle_script_id={0}'
for a in x:
   print a['href'][-6:]
   xmlLink =  xmlLinkBase.format(a['href'][-6:])
   #webbrowser.open_new_tab(xmlLink)
   print xmlLink

str.format Docs