C＃拆分xml innertext或解析innerxml

Question

I have an XML file with a structure similar to this

<entry name="something">
  <members>
    <member>aaa</member>
    <member>bbb</member>
  </members>
</entry>
<entry name="something_else">
  <members>
    <member>ccc</member>
    <member>ddd</member>
  </members>
</entry>

I need to be able to get the values out of each of the member nodes to store in a datatable. if i use the innertext property, it concatenates the values (aaabbb). there is nothing discernible to split the string on. I can also use the inner XML but then i just get a string with the XML structure (aaa bbb<\\member>)

What is the best way to get each value out of the XML elements and store it in a string array?

here is what I have been trying.

foreach (XmlNode grpNode in GrpList)
{
    subNode = grpNode.Attributes["name"];
    if (subNode != null)
    {
        Obj = grpNode.Attributes["name"].Value;
    }

    subNode = grpNode["members"];
    if (subNode != null)
    {
        string innerXml = string.Empty;
        innerXml = grpNode["members"].InnerXml.ToString();

        string[] tempArrary = innerXml.Split(new char[] {'>', '<'});
    }
}

Answer 1

You can use Xpath to iterate through Entry nodes and get the members within it like this

 string xml = "<root><entry name='something'>" + "<members>" + "<member>aaa</member>" + "<member>bbb</member>" + "</members>" + "</entry>" + "<entry name='something_else'>" + "<members>" + "<member>ccc</member>" + "<member>ddd</member>" + "</members>" + "</entry></root>"; XmlDocument doc = new XmlDocument(); doc.LoadXml(xml); var memsList = doc.SelectNodes("//entry"); foreach (XmlNode a in memsList) { Console.WriteLine(a.Attributes["name"].Value); var memList = a.SelectNodes("members/member"); foreach(XmlNode x in memList) Console.WriteLine(x.InnerText); } 

Answer 2

You need to iterate the child elements within members , so something like:

foreach (var node in grpNode["members"].ChildNodes)
{
    var value = node.InnerText;
}

That said, you would be better off using LINQ to XML unless you have some specific reason to use XmlDocument . This gives you much more expressive code, for example:

var doc = XDocument.Parse(xml);

var something = doc.Descendants("entry")
    .Where(e => (string)e.Attribute("name") == "something")
    .Single();

var somethingMembers = something.Descendants("member")
    .Select(e => e.Value)
    .ToArray();

Answer 3

This should do the trick:

XDocument xdoc = XDocument.Load(@"Path/to/file");
var result = xdoc.Descendants("member").Select (x => x.Value).ToArray();

Result:

Demo Code

Answer 4

the xml you've provided isn't valid. But assuming you just want the inner text of all member nodes into a string array, I'd just use Linq-To-Xml (XDocument):

var results = XDocument.Parse(xmlString)
                       .Descendants("member")
                       .Select(m => m.Value)
                       .ToArray();

Answer 5

即使您使用的是旧版XmlDocument API，也可以通过抛出.OfType<XmlNode>()来将XmlNodeList转换为通用枚举，从而混合使用一些linq和lambda语法，例如：

var tempArrary = subNode.SelectNodes("member").OfType<XmlNode>().Select(n => n.InnerText).ToArray();