[英]Python 2.7 counting number of strings
I'm trying to count the number of times in a list a string has more than 20 characters. 我试图计算一个字符串中超过20个字符的列表中的次数。
I am trying to use the count method and this is what I keep getting: 我正在尝试使用count方法,这就是我一直得到的:
>>> for line in lines:
x = len(line) > 20
print line.count(x)
edit: sorry for the indentation mistake before 编辑:抱歉缩进错误之前
Think you mean this, 以为你是这个意思,
>>> s = ['sdgsdgdsgjhsdgjgsdjsdgjsd', 'ads', 'dashkahdkdahkadhaddaad']
>>> cnt = 0
>>> for i in s:
if len(i) > 20:
cnt += 1
>>> cnt
2
or 要么
>>> sum(1 if len(i) > 20 else 0 for i in s)
2
or 要么
>>> sum(len(i) > 20 for i in s)
2
In this case, 在这种情况下,
x = len(line) > 20
x is a boolean, which cannot be "counted" in a string. x是一个布尔值,不能在字符串中“计数”。
>>> 'a'.count(False)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: expected a character buffer object
You need to actually have a string or similar type (Unicode, etc.) to be counted in the line. 您实际上需要在该行中计算一个字符串或类似类型(Unicode等)。
I'd recommend using a simple counter for your purpose: 我建议您使用一个简单的计数器:
count = 0
for line in lines:
if len(line) > 20:
count += 1
print count
>>> for line in lines:
... x = len(line) > 20
here, x
is a boolean type ( True
or False
in Python), because len(line) > 20
is a logic expression. 此处,
x
是布尔类型(在Python中为True
或False
),因为len(line) > 20
是逻辑表达式。
You may figure out the problem by debugging: 您可以通过调试找出问题所在:
>>> for line in lines:
... x = len(line) > 20
... print x
Besides, x = len(line) > 20
is not a condition expression. 此外,
x = len(line) > 20
不是条件表达式。 You need to use if
expression: 您需要使用
if
表达式:
>>> count = 0
>>> for line in lines:
... if len(line) > 20:
... count += 1
...
>>> print count
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