[英]javascript syntax to set object property value from external variable
I can better explain my case by code snippet 我可以通过代码片段更好地解释我的情况
var cascadiaFault = new google.maps.Polyline({ paths: [ new google.maps.LatLng(49.95, -128.1), new google.maps.LatLng(46.26, -126.3), new google.maps.LatLng(40.3, -125.4) ] });
the value of paths
property should be assigned from external variable pathsTemp
paths
属性的值应从外部变量pathsTemp
分配
var pathsTemp = []; for (var i = 0; i < boxes.length; i++) { var bounds = boxes[i]; // Perform search over this bounds pathsTemp.push(bounds.getCenter()); } var cascadiaFault = new google.maps.Polyline({ paths: pathsTemp; });
Its not working.. 它不起作用..
Other options that I tried 我尝试过的其他选择
paths = pathsTemp;
-- Not working -不工作
paths: paths.push(pathsTmep)
-- No syntactic error but, uncaught reference error at runtime when this line is reached paths: paths.push(pathsTmep)
-没有语法错误,但是到达此行时在运行时未捕获参考错误
PS: I don't have javascript background and unfortunately I don't have time to start reading the syntax and rules from scratch (However, I can understand most of the js code already written) PS:我没有javascript背景,但是我没有时间开始从头开始阅读语法和规则(但是,我可以理解已经编写的大多数js代码)
Well, I got what the problem is 好吧,我明白了问题所在
paths: pathsTemp
正确的语法是paths: pathsTemp
var pathsTemp = []; for (var i = 0; i < boxes.length; i++) { var bounds = boxes[i]; // Perform search over this bounds pathsTemp.push(bounds.getCenter()); } var cascadiaFault = new google.maps.Polyline({ paths: pathsTemp });
path
instead of paths
上面的代码在语法上是正确的,但是问题在于它应该是path
而不是paths
Though the sample example presented at https://developers.google.com/maps/documentation/javascript/geometry#isLocationOnEdge 尽管示例示例位于https://developers.google.com/maps/documentation/javascript/geometry#isLocationOnEdge
uses paths
, it works with path
for me. 使用paths
,它对我来说适用于path
。 May be a typo in API documentation 可能是API文档中的错字
As expected, documentation bug logged 不出所料, 记录了文档错误
with reference to this stackoverflow discussion 参考此stackoverflow讨论
for the person who down voted the question : please take a look at this misleading example snippet from google documentation and change your opinion if it makes sense to you (Reputation matters a lot here, for a beginner like me) 对于不赞成该问题的人:请看一下Google文档中的这个令人误解的示例片段,如果对您有意义,请更改您的意见(在这里声望非常重要,对于像我这样的初学者而言)
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