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PHPUnit-如何在PHPUnit_Framework_TestCase中实例化我的pdo类?

[英]PHPUnit - How to instantiate my pdo class in PHPUnit_Framework_TestCase?

How can I instantiate my pdo class in PHPUnit_Framework_TestCase? 如何在PHPUnit_Framework_TestCase中实例化我的pdo类?

for instance, this is my \\test\\SuitTest.php , 例如,这是我的\\test\\SuitTest.php

namespace Test;

use PHPUnit_Framework_TestCase;

class SuiteTest extends PHPUnit_Framework_TestCase
{
    protected $PDO = null;

    public function __construct()
    {
        parent::__construct();
        $this->PDO = new \Foo\Adaptor\PdoAdaptor(); // the pdo is not instantiated at all - I think!
    }

    protected function truncateTables ($tables)
    {
        foreach ($tables as $table) {
            $this->PDO->truncateTable($table);
        }
    }

    /**
     * DO NOT DELETE, REQUIRED TO AVOID FAILURE OF NO TESTS IN FILE
     * PHPUnit is ignoring the exclude in the phpunit.xml config file
     */
    public function testDummyTest()
    {
    }
}

I want to use the pdo class that I use it for development and production, which is in, \\app\\source\\Adaptor\\PdoAdaptor.php , 我想使用用于开发和生产的pdo类,位于\\app\\source\\Adaptor\\PdoAdaptor.php

<?php

namespace Foo\Adaptor;

use PDO;

class PdoAdaptor
{
    protected $PDO = null;
    protected $dsn = 'mysql:host=localhost;dbname=phpunit', $username = 'root', $password = 'xxxx';

    /*
     * Make the pdo connection.
     * @return object $PDO
     */
    public function connect()
    {
        try {
            $this->PDO = new PDO($this->dsn, $this->username, $this->password, array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"));
            $this->PDO->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

            // Unset props.
            unset($this->dsn);
            unset($this->username);
            unset($this->password);
        } catch (PDOException $error) {
            // Call the getError function
            $this->getError($error);
        }
    }

    public function truncateTable($table)
    {
        $sql = "TRUNCATE TABLE $table";
        $command = $this->PDO->prepare($sql);
        $command->execute();
    }
}

I get this error when I run phpunit for testing my codes, 当我运行phpunit来测试我的代码时出现此错误,

Fatal error: Call to a member function prepare() on null 致命错误:在null上调用成员函数prepare()

The pdo is not instantiated at all inside the construct method in SuiteTes t - I think! SuiteTes t的construct方法中SuiteTes没有实例化SuiteTes我想!

This is my dir structure, 这是我的目录结构,

在此处输入图片说明

Use the setUpBeforeClass method (note: it's static) 使用setUpBeforeClass方法(注意:它是静态的)

protected static $pdo;

public static function setUpBeforeClass()
{
    static::$pdo = new PdoAdapter();
}

Then just access your pdo instance with static::$pdo or self::$pdo in your tests. 然后只需在测试中使用static::$pdoself::$pdo访问您的pdo实例。

You should use the setup method instead of overwriting the PHPUnit_Framework_TestCase constructor, ie just replace the constructor definition in SuiteTest class with: 您应该使用setup方法,而不是覆盖PHPUnit_Framework_TestCase构造函数,即仅将SuiteTest类中的构造函数定义替换为:

public function setup()
{
    $this->PDO = new \Foo\Adaptor\PdoAdaptor();
}

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