当用作函数中的参数时，swift 闭包可以设置为默认值吗？

Question

A pretty handy feature of Swift functions is that function parameters can have default values :

func someFunction(parameterWithDefault: Int = 42) {
    //if no arguments are passed to the function call,
    //value of parameterWithDefault is 42
}

If a parameter is a closure, is there a way to make it have a default value? See the example below:

func sendBody(
    body: NSData? = nil,
    success: (data: NSData) -> Void,
    failure: (data: NSData?) -> Void) {
}

Is there a way to not force the developer to pass a value for success or failure when calling sendBody ?

Answer 1

Yes, functions are just values, so you can supply them as defaults

// just to show you can do it with inline closures or regular functions
func doNothing<T>(t: T) -> Void { }

func sendBody(
    body: NSData? = nil,
    success: (data: NSData) -> Void = { _ in return },
    failure: (data: NSData?) -> Void = doNothing
)
{  }

Alternatively, you could make them optional, that way you can detect if the caller passed one:

func sendBody(
    body: NSData? = nil,
    success: ((NSData) -> Void)? = nil,
    failure: ((NSData?) -> Void)? = nil
    )
{ success?(NSData()) }

sendBody(success: { _ in print("ah, yeah!") })

Also worth noting if you're doing this: if the caller uses the trailing closure syntax, this will be the last closure in the argument list. So you want the last one to be the one the user is most likely to want to supply, which is probably the success closure:

func sendBody(
    body: NSData? = nil,
    success: ((NSData) -> Void)? = nil,
    failure: ((NSData?) -> Void)? = nil
    )
{
    if success != nil { print("passed a success closure") }
    if failure != nil { print("passed a failure closure") }
}

// this prints "passed a failure closure"
sendBody { data in
    print("which closure is this?")
}

Other than this, the order in the function declaration doesn't matter to the caller – defaulted arguments can be supplied in any order.

Answer 2

You could do something like this,

let defaultSuccess: NSData -> Void = {
    (data: NSData) in

}

let defaultFailure: NSData? -> Void = {
    (data: NSData?) in
}

func sendBody( body: NSData? = nil, success: (data: NSData) -> Void = defaultSuccess, failure: (data: NSData?) -> Void = defaultFailure) {
}

Then, you may be able to call either one of these methods. Notice sendBody which is called with default parameters.

sendBody()
sendBody(body: , success: , failure: )

You can also call with all the variants like passing just one of the argument in the above method, for that you have to call it with named parameter.

sendBody()
sendBody(body:)

sendBody(failure: )
sendBody(success:)

sendBody(body: , success: , failure: )

Answer 3

My preferred way to specify public facing closures - in particular completion closures which you might want to store somewhere for later - is to define a typealias for them, like this:

public typealias FooCompletion = (String) -> Void

Then in the public facing function you can easily make it optional like this:

var onCompletion: FooCompletion? = nil

public func foo(completion: FooCompletion? = nil) {
    // Store completion for later
    onCompletion = completion
}

The completion parameter is optional, so it's allowed to be nil , and the default value is nil , meaning the caller doesn't have to specify it. Also, because you use the type in more than one place, if you need to change its definition during development there's only one place to do so. It's easy to call too:

private func someBackgroundThing() {
    var completionString = "done"
    ...
    onCompletion?(completionString)
}

Answer 4

How to set a default value for a function parameter. Swift 4 and (probably) 5.

func someFunction(age: Int, doSomething:@escaping () -> Void = {}){
  //do work here

  //
  doSomething()
}

Then you can do this

someFunction(age: 18) {
  print("hello")
}

someFunction(age: 19)

You may or may not need to use the @escaping keyword. See Swift @escaping and Completion Handler for that.