正则表达式只获取每行的第一个单词

Question

I have a text file

@sp_id      int,    
@sp_name                varchar(120),
@sp_gender              varchar(10),
@sp_date_of_birth       varchar(10),
@sp_address             varchar(120),
@sp_is_active           int, 
@sp_role            int

Here, I want to get only the first word from each line. How can I do this? The spaces between the words may be space or tab etc.

Answer 1

Here is what I suggest:

Find what : ^([^ \\t]+).*

Replace with : $1

Explanation : ^ matches the start of line, ([^ \\t]+) matches 1 or more (due to + ) characters other than space and tab (due to [^ \\t] ), and then any number of characters up to the end of the line with .* .

See settings:

In case you might have leading whitespace, you might want to use

^\s*([^ \t]+).*

Answer 2

Find What: ^(\\S+).*$

Replace by : \\1

You can simply use this to get the first word.Here we are capturing the first word in a group and replace the while line by the captured group.

Answer 3

使用/^\\w+/gm查找每行的第一个单词。