[英]How to get which condition has failed if any in a single sql query
This might be odd or not... but I need to find out which condition out of 3 has failed if any... 这可能是奇怪的,也可能不是。。。但是我需要找出3个条件中有哪个失败了...
I explain... 我解释...
In my query I have 3 condition if all goes fine then no problem, but if one of those conditions fail I need to know which condition or conditions have fail so that I can build a proper response... 在我的查询中,如果所有条件都正常,那么我有3个条件,但是没有问题,但是如果其中一个条件失败,则我需要知道哪个条件或多个条件失败,以便我可以建立适当的响应...
Example: 例:
if(strlen($k) == 16 && filter_var($em, FILTER_VALIDATE_EMAIL)) {
$con = $c->Con();
$q = $con->query("SELECT COUNT(*) FROM table WHERE v = '$k' AND ema = '$em' AND ve = '0'");
$r = $q->fetch_row();
if($r > 0) { $q = $con->query("UPDATE table SET ve = '1' WHERE v = '$key' AND emails = '$em'");
if($q){
$mss = 'Ready'; // MS 1
}
} else {
$mss = 'It was ready'; // MS 2
}
} else {
$mss = 'Something is wrong!'; // MS 3
}
So the first query has 3 conditions if all are ok then go to the next "query", BUT, how do I know is one of the conditions fail?... what if [v] is not a match, or if the email is not a match or if ve is not a match... that way I can show a proper message on the MS 2.... instead of a general message... 所以第一个查询有3个条件,如果一切都OK,然后转到下一个“查询”,但是,我怎么知道其中一个条件失败?...如果[v]不匹配,或者如果电子邮件,该怎么办?不匹配或ve不匹配...那样我可以在MS 2上显示正确的消息...而不是一般消息...
if v is not equal to $k then $mss = 'Your key is not a match'; 如果v不等于$ k,则$ mss ='您的密钥不匹配';
if emails is not equal to $ema then $mss = 'Your email was not fund'; 如果电子邮件不等于$ ema,则$ mss ='您的电子邮件没有资金';
if ve is not equal to 0 then $mss = 'Your key has no value'; 如果ve不等于0,则$ mss ='您的密钥没有值';
the thing is that I would like to keep it as short and clean as possible, I can do a separate query for each one of the conditions which is a lazy way to do it but effective... 问题是我想使其尽可能短而整洁,我可以针对每个条件进行单独的查询,这是一种懒惰的方法,但是有效...
I can come up with a clunky solution that mostly shifts the work to PHP. 我可以提出一个笨拙的解决方案,主要将工作转移到PHP。
SELECT v, ema, ve FROM table WHERE v = '$k' OR ema = '$em' OR ve = '0';
Pseduocode 伪码
while( $row = fetch_row($result) ){
if( 1 and 2 and 3 ){
//SUCCESS
}
elseif( NOT 1 ){
//1 is the problem
}
elseif( NOT 2 ){
//2 is the problem
}
elseif( NOT 3 ){
//3 is the problem
}
}
1,2,3 are the condition (eg 1 = ($row['v'] == $k)) 1,2,3是条件(例如1 =($ row ['v'] == $ k))
You'll have to figure out what to do about multiple rows, ideally the schema would prevent that. 您必须弄清楚如何处理多行,理想情况下,架构可以避免这种情况。
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