使用正则表达式（包括空格）获取字符串中的所有字母

Question

How would I extract all alpha characters (including space) like for example: 我将如何提取所有字母字符（包括空格），例如：

@john camel07 st.doe!

where I only want to get john camel stdoe . 我只想得到john camel stdoe 。

I tried using the regex from this another SO question but it does not work. 我尝试从另一个SO问题中使用正则表达式，但是它不起作用。

Answer 1

$re = "/[^a-zA-Z ]+/"; 
$str = "@john camel07 st.doe!"; 
$subst = ""; 

$result = preg_replace($re, $subst, $str);

You can simply replace by empty string all non alpha and space characters.See demo. 您可以简单地用empty string替换所有非字母和空格字符。请参见演示。

Answer 2

If your data contains unicode, this should work a bit better: 如果您的数据包含unicode，则效果会更好一些：

echo preg_replace("/[^[:alpha:][:space:]]/ui", '', '@john camel07 st.doe!');