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使用List <>中的映射和索引收集目录和子目录

[英]Collect Directory and Sub Directories with mapping and index in a List<>

I want to collect the directory listing in a collection(a List<> perhaps) my directory structure is like : 我想将目录列表收集在一个集合中(也许是List <> ),我的目录结构是这样的:

MainFolder\ParentFolder1\SubFolder1    
                        \SubFolder2    
                        \SubFolder3

MainFolder\ParentFolder2\SubFolder1
                        \SubFolder2
                        \SubFolder3

I want to list all the subfolders mapped to their parent directories. 我想列出所有映射到其父目录的子文件夹。

Also, the records will have index of ParentFolder 0-n in MainFolder and index of SubFolder 0-n in each ParentFolder. 此外,记录还将在MainFolder中具有ParentFolder 0-n的 索引,在每个ParentFolder中具有SubFolder 0-n的索引。

I did tried below but not yet achieved 我在下面尝试过但尚未实现

lstParents = (from f in Directory.GetDirectories(MainFolder)
             select  Data
         {
        parent =f
         }).ToList();

var lstSubDir = (from f in lstParents.Select(m => Directory.GetDirectories(m.parent).ToList());

You can use this overload of the GetDirectories method to find all subdirectories recursively: 您可以使用GetDirectories方法的重载来递归查找所有子目录:

var mainDirectory = new DirectoryInfo(@"C:\temp\MainFolder");
var subDirectories = mainDirectory.GetDirectories("*", SearchOption.AllDirectories);

Then you can map them into pairs of directory/parent like this: 然后,您可以将它们映射为成对的目录/父目录,如下所示:

var mappedDirectories = subDirectories.Select(sd => new { Parent=sd.Parent, Child=sd });

If you want to exclude the first level of subdirectories ( ParentFolder1 and ParentFolder2 , in your case) you can filter them like this: 如果要排除第一级子目录(在您的情况下为ParentFolder1ParentFolder2 ),可以按以下方式过滤它们:

var mappedDirectories = subDirectories
    .Where(sd => sd.Parent.FullName != mainDirectory.FullName)
    .Select(sd => new { Parent=sd.Parent, Child=sd });

EDIT after you've asked for indices: 请求索引后进行编辑:

You stated, that you'll always only have a nesting level of 2, the following piece of code will not work for deeper directory structures. 您说过,嵌套级别始终为2,以下代码对更深的目录结构不起作用。

var mainDirectory = new DirectoryInfo(@"C:\temp\MainFolder");
var firstLevelDirectories = mainDirectory.GetDirectories().Select((f1,i) => new { 
  Parent = f1, 
  ParentIndex = i 
});

var secondLevelDirectories = firstLevelDirectories
  .SelectMany(f1 => f1.Parent.GetDirectories().Select((f2,i) => new {
    f1.Parent, 
    f1.ParentIndex, 
    Child = f2, 
    ChildIndex = i
} ));

This will give you a list of records, each containing 这将为您提供记录列表,每个记录包含

  • the parent directory, 父目录,
  • the parent directory index, 父目录索引,
  • the child directory and 子目录和
  • the child directory index within its parent. 子目录在其父目录中的索引。

Try this recursive algorithm. 试试这个递归算法。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;

namespace ConsoleApplication2
{
    class Program
    {
        static void Main(string[] args)
        {
            Folders folders = new Folders(@"c:\temp", null);
            Console.ReadLine();
        }
    }
    public class Folders
    {
        public string path { get; set; }
        List<string> files = new List<string>();
        List<Folders> folders = new List<Folders>();
        Folders parent = null;

        public Folders(string path, Folders parent)
        {
            this.parent = parent;
            this.path = path;
            foreach (string folderPath in Directory.GetDirectories(path))
            {
                Folders newFolder = new Folders(folderPath, this);
                folders.Add(newFolder);
            }
            files = Directory.GetFiles(path).ToList();
            int pathlength = path.Length;
            Boolean first = true;
            Console.Write(path);
            if (files.Count == 0) Console.WriteLine();
            foreach (string file in files)
            {
                string shortname = file.Substring(file.LastIndexOf("\\") + 1);
                if (first)
                {
                    Console.WriteLine("\\" + shortname);
                    first = false;
                }
                else
                {

                    Console.WriteLine(new string(' ', pathlength + 1) + shortname);
                }
            }

        }
    }
}
​

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