[英]How can I join 3 tables in SQL
Here is the query I created : 这是我创建的查询:
$query = "SELECT address_details.company, address_details.po_box,
address_details.town, letter_details.address_id,
letter_details.attn, letter_details.create_date,
letter_details.ref_no, letter_details.refference,
letter_details.letter_body, letter_details.print_date
FROM letter_details
join address_details ON address_details.id = letter_details.address_id
join signatories ON (letter_details.id = signatories.id)
WHERE letter_details.id='" .$_GET['id'] . "'";
Try using this query. 尝试使用此查询。
$query = "SELECT ad.company, ad.po_box,
ad.town, ld.address_id,
ld.attn, ld.create_date,
ld.ref_no, ld.refference,
ld.letter_body, ld.print_date
FROM letter_details ld
left join address_details ad ON (ad.id = ld.address_id)
left join signatories s ON (ld.id = s.id)
WHERE ld.id='" .$_GET['id'] . "'";
First, you should alias for better readibility, 首先,您应该使用别名以提高可读性,
check if you get something in $_GET[id] 检查您是否在$ _GET [id]中得到了东西
echo $_GET[id];
then assign it, (or you may set it as well, if you're using a class) 然后分配它(或者,如果您使用的是类,也可以对其进行设置)
$fltr = $_GET[id];
And, try to use LEFT JOIN ; 并且,尝试使用LEFT JOIN;
SELECT b.company, b.po_box,
b.town, a.address_id,
a.attn, a.create_date,
a.ref_no, a.refference,
a.letter_body, a.print_date
FROM letter_details AS a LEFT JOIN address_details AS b ON b.id = a.address_id
LEFT JOIN signatories AS c ON (a.id =c.id)
WHERE a.id='$fltr'
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