[英]How can i share variables between views, with the same controller in AngularJS?
I have this controller... 我有这个控制器...
app.controller('UploadController', ['$scope', 'Upload', '$timeout', function ($scope, Upload, $timeout) {
$scope.$watch('files', function () {
$scope.upload($scope.files);
});
$scope.upload = function (files) {
if (files && files.length) {
for (var i = 0; i < files.length; i++) {
var file = files[i];
}
}
};
}]);
i'm assigning to the var file
the temp obtained from files[i]
, so i can display the temp like a preview on my view. 我正在将从
files[i]
获得的温度分配给var file
,因此我可以像预览一样在我的视图上显示该温度。
<section ng-controller="UploadController">
<img ngf-src="files[0]" ng-show="files[0].type.indexOf('image') > -1">
</section>
but what I really need is to show the temp in my modal view. 但是我真正需要的是在模态视图中显示温度。
<section ng-controller="UploadController">
<img ngf-src="files[0]" ng-show="files[0].type.indexOf('image') > -1">
</section>
The modal view have the same controller and the same "img" attributes, but when i display the modal view the controller RESTART , this is the point of the question, i need to learn how can i keep the value of a variable in the same controller but in an different view without the need to redo actions. 模态视图具有相同的控制器和相同的“ img”属性,但是当我显示模态视图时,控制器RESTART ,这是问题的重点,我需要学习如何将变量的值保持在相同的位置。控制器,但视图不同,无需重做操作。
basically i need: when displaying a view, my controller does not restart . 基本上我需要:显示视图时,我的控制器不会重新启动 。
<img src="">
takes image's url or image's path. <img src="">
采用图片的网址或图片的路径。 Once you upload the image to the server. 将映像上传到服务器后。 If you could returns the image url instead of the image data, the image should be displayed properly.
如果可以返回图像URL而不是图像数据,则应正确显示图像。
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