iOS-如何在UIViewController的首选位置上显示自定义弹出视图

Question

I have a view controller that displays a bunch of buttons for music control. One of them is a volume control located at the button. I wish to display a mini pop-up view that contains just a vertical slider when the volume control button is clicked. How can I achieve this?

The first solution that came up on my mind is setting a slider that is hidden initially, and will be shown after the button is clicked. But I don't want this solution. I want a more "professional" way. I also searched through the net about pop up views, most of them are something like a custom alert dialog in which the background is dimmed, and I don't want that.

So please help me if you can. Thanks in advance!

Answer 1

try this code:

- (void)viewDidLoad
{
       [super viewDidLoad];
       popupView.hidden=YES;
}

this code place in Show Slider button Click event

[self showSliderPopup];// call method
popupView.hidden=NO;

create popup method

-(void) showSliderPopup{
    UISlider *slider=[[UISlider alloc]initWithFrame:CGRectMake(10, 0, 300, 300)];
    CGAffineTransform trans=CGAffineTransformMakeRotation(M_PI_2);
    slider.transform=trans;
    slider.minimumValue=1;
    slider.maximumValue=100;
    slider.continuous=NO;
    [slider addTarget:self action:@selector(sliderChanhge:) forControlEvents:UIControlEventValueChanged];

   popupView=[[UIView alloc]initWithFrame:CGRectMake(10, 10, 300, 350)]; // set popup frame your require position 
    [popupView addSubview:slider];
    [self.view addSubview:popupView];
}

Slider Change method

-(IBAction)sliderChanhge:(id)sender
{
     NSLog(@"%d",(int)slider.value);
}