从函数传递时如何查看gdb中的数组内容

Question

I would like to see the contens of my array when passed as an argument to a function, through gdb.

Say, I have some code which looks like

#include <stdio.h>

int fun(int b[], int len)
{ 
 int i = 0;

 /* how do I see the contents of array b[] in gdb */
 for(i = 0; i < len; ++i)
     printf("%d ", b[i]);
}

int main()
{
    int a[] = {1,2,3,4,5};

    fun(a, sizeof(a) / sizeof(*a));
    return 0;
}

In gdb, a[] looks as follows

(gdb) disp a
1: a = {1, 2, 3, 4, 5}

But If I try to print b[], since it's a pointer (as array is passed as a pointer), the contents looks like this

fun (b=0x7fffffffdf90, len=5) at main.c:14
(gdb) disp b
2: b = (int *) 0x7fffffffdf90

I want to be able to see the contents of b[] just like I'm seeing a[] so it helps me debug.

How can I do this?

Answer 1

您可以使用人工数组显示如下：

*b@len