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如何使用jQuery / Ajax将数据传递到URL

[英]How to pass data using jQuery/ Ajax to a URL

How to pass the fetched data using $.get() from a URL to a particular URL with query_string that can be retrieved using $_GET() in PHP. 如何使用$ .get()将获取的数据从URL传递到带有query_string的特定URL,可以在PHP中使用$ _GET()进行检索。 I'm using following but not working. 我正在使用关注但无法正常工作。 I want to pass the fetched data into following parameter http://example.com/data?data=FETECHED_DATA 我想将获取的数据传递到以下参数http://example.com/data?data=FETECHED_DATA

<?php
$ip_address=$_SERVER['REMOTE_ADDR'];    
echo '<script>
$.get( "http://ipinfo.io/'.$ip_address.'/org", function( data ) {
$.ajax({
  type: "GET",
  url: "http://example.com/data",
  data: data,
  success: success,
  dataType: dataType
});
});
</script>';?>

Well, don't recommended PHP to fetch and send data 好吧,不建议PHP获取和发送数据

I believe this will do what you want 我相信这会做你想要的

<?php
$ip_address=$_SERVER['REMOTE_ADDR'];    
echo '<script>
$.get("http://ipinfo.io/'.$ip_address.'/org", function(data) {
    $.ajax({
        type: "GET",
        url: "http://example.com/data",
        data: {data : data},
        success: success,
        dataType: dataType
    });
});
</script>';?>

the only change is data: data changed to data: {data: data} 唯一的变化是数据:数据已更改为数据:{data:data}

that's a lot of data :p 大量的数据:p

see this cut down mock up, http://jsfiddle.net/cm8o5dk8/ if you have a decent browser that can show you the network "usage" you'll see that the mockup fails trying to GET http://example.com/data?data=AS15169+Google+Inc.%0A - the %0A comes back from ipinfo.io 如果您有一个不错的浏览器可以向您显示网络“使用情况”,请参阅此简化模型http://jsfiddle.net/cm8o5dk8/ ,您将看到该模型无法尝试获取http://example.com/data?data=AS15169+Google+Inc.%0A从ipinfo.io返回

Thanks it worked 谢谢工作

$.get("http://ipinfo.io/8.8.8.8/org", function(data) {
    $.ajax({
        type: "GET",
        url: "http://example.com/data",
        data: {data : data},
        success: function() {},
        dataType: 'json'
    });
});

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