简体   繁体   English

使用php和mysql中的下拉选择列表从databse检索数据

[英]Retrieving data from databse using the dropdown selected list in php and mysql

I have texbox and dropdown list which is populated from mysql database. 我有从MySQL数据库填充的texbox和下拉列表。 I want to retrieve data from database and wants to display in textbox using dropdown selected list, without refreshing the page. 我想从数据库中检索数据,并希望使用下拉列表选择列表显示在文本框中,而不刷新页面。 Here is my code and Thanks in Advance. 这是我的代码,在此先感谢。

<select name="select1" class="form-control" id="dropdownlist1">
      <option id="0">-- Select the Company --</option>
      <?php
          require("dbcon.php");

          $getallcompanies = mysql_query("SELECT * FROM ifcandetails6");

          while($viewallcompanies = mysql_fetch_array($getallcompanies)){
              ?>
      <option id="<?php echo $viewallcompanies['tcuid']; ?>"><?php echo $viewallcompanies['tcname'] ?></option>
      <?php
          }
           ?>

  </select>

Input Textbox: 输入文字框:

 <input type="text" id="field1" value="<?php echo $viewallcompanies['tccontact']?>" disabled/>

Separate things out like this: 像这样将事情分开:

<?php

require("dbcon.php");

$query = mysql_query("SELECT tcuid, tcname, tccontact FROM ifcandetails6");
while($row = mysql_fetch_array($query)){
    $contacts[] = $row['tccontact'];
    $companies[] = $row;   
}
?>

<select name="select1" class="form-control" id="dropdownlist1">
    <option id="0">-- Select the Company --</option>
    <?php foreach($companies as $company) { ?>
        <option id="<?= $company['tcuid']; ?>"><?= $company['tcname'] ?></option>
    <?php }  ?>
</select>
<?php foreach($contacts as $contact) { ?>
    <input type="text" id="field1" value="<?= $contact['tccontact']?>"/>
<?php }  ?>

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

相关问题 使用下拉列表PHP / MySQL / HTML从数据库中检索数据 - Retrieving data from database with dropdown list PHP/MySQL/HTML 从使用 PHP 从 MySQL 检索数据的动态列表中的选定选项中获取值 - Get value from a selected option in a dynamic list retrieving data from MySQL with PHP 使用php从mysql中选择数据,显示在html下拉列表中,并通过javascript插入所选值作为URL参数 - Select data from mysql with php, display in html dropdown list and insert selected value as URL parameter via javascript 使用 PHP 从下拉菜单中检索值 - Retrieving a value from a dropdown menu using PHP 使用PHP和AJAX从MySQL数据库中选择和检索数据 - Selecting and retrieving Data from a MySQL Database using PHP and AJAX 使用AJAX从databse填充HTML下拉列表 - Populating HTML dropdown from databse using with AJAX 使用php在angular js中从databse获取数据 - fetch data from databse in angular js using php 如果没有从下拉列表中选择任何值,则允许文本框使用php,mysql,javascript添加到mysql表中 - If no value selected from dropdown, allow textbox to add to mysql table using php, mysql, javascript 从mysql和php检索json数据到jquery - retrieving json data from mysql and php into jquery 使用 ajax 和 php 从数据库检索数据到 html 下拉列表时出现问题? - Getting issue while retrieving data from database into html dropdown using ajax and php?
 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM