[英]Extracting data from api using powershell tool Invoke-RestMethod
I am trying to get JSON details from an api using powershell. 我正在尝试使用Powershell从api获取JSON详细信息。 I do not have any expereince with power shell, but I guess Invoke-RestMethod would be helpful.
我对Power Shell没有任何经验,但是我想Invoke-RestMethod会有所帮助。
the api I am trying to use is : 我尝试使用的api是:
api.spotcrime.com/crimes.json?lat=30.639155&lon=-96.3647937&radius=0.02&key=spotcrime-private-api-key api.spotcrime.com/crimes.json?lat=30.639155&lon=-96.3647937&radius=0.02&key=spotcrime-private-api-key
Please read the online documentation: Invoke-RestMethod 请阅读在线文档: Invoke-RestMethod
Here is a sample showing how to access the data returned from this API: 这是显示如何访问此API返回的数据的示例:
$uri = 'api.spotcrime.com/crimes.json'
$params = @{
lat = '30.639155'
lon = '-96.3647937'
radius = '0.02'
key = 'spotcrime-private-api-key'
}
$crimes = Invoke-RestMethod -Uri $uri -Body $params |
Select-Object -ExpandProperty crimes
$crimes | Format-Table -AutoSize
In this dataset we have an object named crimes which contains an array of records. 在此数据集中,我们有一个名为Crimes的对象,其中包含一组记录。 Expanding the crimes object and storing it to a
$crimes
variable will allow us to work with the records more easily. 扩展犯罪对象并将其存储到
$crimes
变量将使我们能够更轻松地处理记录。
Notice how Invoke-RestMethod
automatically detects and converts JSON into objects. 注意
Invoke-RestMethod
如何自动检测JSON并将其转换为对象。 No need to use ConvertFrom-Json
. 无需使用
ConvertFrom-Json
。
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