[英]Filter edges by property in a subquery - orientdb sql
I have the following OrientDB SQL query that returns the username and country of all the friends of user #12:0
.我有以下 OrientDB SQL 查询,它返回用户
#12:0
的所有朋友的用户名和国家/地区。
select
username, country
from (select
expand( both('friends') )
from
users
where
@rid = #12:0)
But, the friends
edge has a property years
with an integer.但是,
friends
边缘有一个整数years
的属性。 I only want those friends of #12:0
that have friends.years > 3
.我只想要那些拥有
friends.years > 3
的#12:0
friends.years > 3
。
I have tried我试过了
SELECT username, country from (SELECT expand(outE('friends')[years > 3].inV()) FROM #12:0)
SELECT username, country from (SELECT expand(both('friends')[years = 2]) FROM #12:0)
and various plays on the same query.以及对同一查询的各种播放。
Thanks, all!谢谢大家!
create class User extends V
create property User.username string
create property User.country string
create class friends extends E
create property friends.year integer
create vertex User content {'username':'u1', 'country':'PT'}
create vertex User content {'username':'f1', 'country':'AW'}
create vertex User content {'username':'f2', 'country':'CN'}
create edge friends
from (select from User where username = 'u1')
to (select from User where username = 'f1')
content {'years':3}
create edge friends
from (select from User where username = 'f2')
to (select from User where username = 'u1')
content {'years':4}
I believe this is your situation.我相信这就是你的情况。 You can:
你可以:
select expand(bothE('friends')[years = 3].inV())
from (select from User where username = 'u1')
But, for what I know, the following is not yet supported:但是,据我所知,尚不支持以下内容:
select expand(bothE('friends')[years > 3].inV())
from (select from User where username = 'u1')
Another option is to wrap the core query with another nested query:另一种选择是用另一个嵌套查询包装核心查询:
select * from (
select expand(both('friends'))
from (select from User where username = 'u1')
)
where years > 3
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