通过PartialView方法返回视图

Question

I want use ajax to prevent refresh my pages and for this I want return Views by PartialView method from controller on ajax call.

The questions is:

1. Is it good way to return a View as PartialView ?
2. How should I set path of views in PartialView method in Controller ?

For example for _Index view in Views/BasicInfo/_Index path, I try PartialView("~/Views/BasicInfo/_Index"); , PartialView("~/Views/BasicInfo/_Index.chtml"); , PartialView("BasicInfo/_Index"); , and get error as not found the view

EDIT

How specified view name into PartialView method, if view is in a folder out of the Shared folder and out of related view folder. For example My controller is name is controller1 and my View is in this path Views/BasicInfo/_Index ?

Answer 1

You should have this

• MyController

  • ActionResult -> Index
  • ActionResult -> IndexPartial

• Views

  • My
    • Index.cshtml (View)
    • IndexPartial.cshtml (PartialView)

Where:

Index.cshtml as complete view will have rendered the partial view with passed model (why so? to prevent code duplication)

@model YourModelType
@{
    ViewBag.Title = "View Index";
    Layout = "~/Views/Shared/_Layout.cshtml";
}

@Html.Partial("IndexPartial", Model)

IndexPartial.cshtml is the partial view, something like

@model YourModelType

<h2>Some Title</h2>
 <div>
<h4>YourModel</h4>
<hr />
<dl class="dl-horizontal">
    <dt>
        @Html.DisplayNameFor(model => model.Property1)
    </dt>

    <dd>
        @Html.DisplayFor(model => model.Property1)
    </dd>

    <dt>
        @Html.DisplayNameFor(model => model.Property2)
    </dt>

    <dd>
        @Html.DisplayFor(model => model.Property2)
    </dd>
</dl>

Now when you want the full View use MyController/Index and when you want Partial View instead you can get it with MyController/IndexPartial

Or you can use parameter on you action to specify the output:

public ActionResult GetMyView(bool? partial)
        {
           var model  = something;
           if (partial != null && partial)
             { 
                return PartialView("MyViewPartial", model)
             }

            return View("MyView", model);
        }

call for partial = yourHost/controller/GetMyView?partial=true

Now back to your question, yes you can return Partial View as View and vice versa. But you will face problems in appended html to pages via ajax (incomplete or overloaded html).

Answer 2

you can use :

public PartialViewResult ActionMethodName() 
{
      return PartialView("_Index.chtml");
}

OR

public ActionResult ActionMethodName() 
{
      return PartialView("_Index.chtml");
}

Answer 3

1. There is no limitation and it's not consider bad practice.

2. You have a typo at the PartialView("~/Views/BasicInfo/_Index.chtml") part of your question.

   You should write return PartialView("~/Views/BasicInfo/_Index.cshtml")

Answer 4

Yea. . Its a best practices to return as Partial View without page load.

 return PartialView("YourPartialView", model)

or else you can use absolute path

return  PartialView("~/Views/AnotherFolder/YourPartialView", model)

Answer 5

This is what I understood by your question : you have a controller name Controller1 which has ActionResult someMethod() and another controller BasicInfo which has a PartialView BasicInfo_Index and you want to return BasicInfo_Index partial view from someMethod():

One you can use the following code in someMethod() to get the partialview of BasicInfo controller :

var DesirePartialView = ViewEngines.Engines.FindPartialView(ControllerContext, "BasicInfo_Index");
        return PartialView(DesirePartialView.View);

Or You can use RedirectToAction() to redircet to action method in BasicInfo controller which returns the specified partialview

Answer 6

What is the return type of the method you're calling in the controller from ajax? It should be something like:

public PartialViewResult LoadPartialView() 
{
      return PartialView("~/Views/BasicInfo/_Index.chtml");
}